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Butoxors [25]
2 years ago
5

Given the net below calculate the surface area. The sides measure 6 by 4, the top and bottom measure 8 by 6 and the front and ba

ck are 8 by 4.

Mathematics
2 answers:
EleoNora [17]2 years ago
8 0

Answer:

152

Step-by-step explanation:

Please give me brainliest, please, I hope this helps

Inessa [10]2 years ago
6 0

Answer:

152

Step-by-step explanation:

So first I find the area of the big rectangle going down, which is 14x8=112

And then I do the flap thingies on the side: 5x4=20x2=40

112+40=152

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Step-by-step explanation:

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3 years ago
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How to evaluate the expression 10(6-5)-3(9-6)
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<span>10(6-5)-3(9-6) = 10 x 1 - 3 x 3 = 10 - 9 = 1</span>
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A traffic engineer monitors the rate at which cars enter the main highway during the afternoon rush hour. From her data she esti
sertanlavr [38]

Answer:

On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.

Step-by-step explanation:

Given that, the rate R(t) at which cars enter the highway is given the formula

R(t)= 100(1-0.0001t^2)

The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.

\therefore \int_0^{30}  100(1-0.0001t^2)\ dt

=[100(t-0.0001\frac{t^3}{3})]_0^{30}

=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]

=2901

The average rate of car is =\frac{\textrm{The number of car}}{Time}

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On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.

8 0
3 years ago
There are 5 marbles in a bag: 4 are blue and 1 is red. What is the probability that a blue marble gets picked?
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Answer:

the answer is 80%

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3 0
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n200080 [17]

Answer:

1) Between 0 and 1 minute the rate of change is 25 ft./min

2) Between 1 and 2 minute the rate of change is 0 ft./min

3) Between 2 and 4 minute the rate of change is -12.5 ft./min

Step-by-step explanation:

1) Between 0, and 1 feet, we have;

The rate of change = (Final height - Initial height)/(Final time - Initial time)

The rate of change = (40 - 15)/(1 - 0) = 25 ft/min

Between 0 and 1 minute the rate of change = 25 ft./min

2) Between 1, and 2 feet, we have;

The rate of change = (40 - 40)/(2 - 1) = 0 ft/min

Between 1 and 2 minute the rate of change = 0 ft./min

3) Between 2, and 4 feet, we have;

The rate of change = (15 - 40)/(4 - 2) = -12.5 ft/min

Between 2 and 4 minute the rate of change = -12.5 ft./min

7 0
3 years ago
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