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dem82 [27]
3 years ago
14

3. A steel pipe of outside diameter 20 mm and thickness 3 mm is

Engineering
1 answer:
Alisiya [41]3 years ago
8 0

The answer is explained in the picture. Thank you. Rate it

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The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any frictio
Dmitrij [34]

Complete Question

The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any friction and calculate their speed v when they reach the horizontal bottom position. At the top position, the radius of the circular path of their mass centers is 21 m, and all six cars have the same mass.V = -18 m What is v?X km/h

Answer:

v=23.6m/s

Explanation:

Velocity v_c=18.0km/h

Radius r=21m

initial velocity uu=19=>5.27778

Generally the equation for Angle is mathematically given by

\theta=\frac{v_c}{2r}

\theta=\frac{18}{2*21}

\theta=0.45

\theta=25.7831 \textdegree

Generally

Height of mass

h=\frac{rsin\theta}{\theta}

h=\frac{21sin25.78}{0.45}

h=20.3m

Generally the equation for Work Energy is mathematically given by

0.5mv_0^2+mgh=0.5mv^2

Therefore

v=\sqrt{u^2+2gh}

v=\sqrt{=5.27778^2+2*9.81*20.3}

v=23.6m/s

3 0
3 years ago
Student A says hazardous waste can take the form of solid, liquid, or gas. Student B says hazardous waste can only take the form
lina2011 [118]

Answer:

Student A

Explanation:

hope this helps have a great day

4 0
3 years ago
How many trips would one rubber-tired Herrywampus have to make to backfill a space with a geometrical volume of 5400 cubic yard?
nikklg [1K]

Answer:

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

Explanation:

a) By volume.

The shrinkage factor is:

\frac{5400cu-yd}{1-0.25} =7200cu-yd

The volume at loose is:

V_{loose} =V_{bank} (1+swell-factor)=7200(1+0.2)=8640cu-yd

If the Herrywampus has a capacity of 30 cubic yard:

\frac{8640cu-yd}{30cu-yd/trip} =288trip

b) By weight

The swell factor in terms of percent swell is equal to:

pounds-per-cubic-yard-loose=\frac{pounds-per-cubic-yard-bank}{\frac{percent-swell}{100}+1 }

pounds-per-cubic-yard-loose=\frac{3000}{\frac{20}{100} +1} =2500lb/cu-yd

The weight of backfill is:

8640cu-yd*2500\frac{lb}{cu-yd} *\frac{1ton}{2000lb} =10800ton

The Herrywampus has a capacity of 40 ton:

\frac{10800}{40ton/trip} =270trip

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

8 0
3 years ago
Q4 a.
dedylja [7]

The Java program that accepts a matrix of M × N order and then interchanges diagonals of the matrix is given below:

<h3>Steps:  </h3>
  • 1. We can only interchange diagonals for a square matrix.
  • 2. Therefore, we would have to create a square matrix of size [M × M].
  • 3. We would check whether the matrix is a square matrix or not. If the matrix is square then follow step 3 else terminate the program.
  • 4. Apply logic for interchange diagonal of the matrix some logic is given below.

<h3>Java Code</h3>

//  Java Program to Accept a Matrix of Order M x N &

//  Interchange the Diagonals

import java.util.Scanner;

public class InterchangeDiagonals {

   public static void main(String[] args)

   {

       // declare variable

       int m, n, i, j, temp;

       // create a object of scanner class

       Scanner sc = new Scanner(System.in);

       System.out.print("Enter number of rows ");

       // take number of rows

       m = sc.nextInt();

       System.out.print("Enter number of columns ");

       // take number of columns

       n = sc.nextInt();

       // declare a mxn order array

       int a[][] = new int[m][n];

       // if block it's execute when m is equals to n

       if (m == n) {

           System.out.println(

               "Enter all the values of matrix ");

           // take the matrix inputs

           for (i = 0; i < m; i++) {

               for (j = 0; j < n; j++) {

                   a[i][j] = sc.nextInt();

               }

           }

           System.out.println("original Matrix:");

           // print the original matrix

           for (i = 0; i < m; i++) {

               for (j = 0; j < n; j++) {

                   System.out.print(a[i][j] + " ");

               }

               System.out.println("");

           }

          // perform interchange

           for (j = 0; j < m; j++) {

               temp = a[j][j];

               a[j][j] = a[j][n - 1 - j];

               a[j][n - 1 - j] = temp;

           }

           System.out.println(

               " after interchanging diagonals of matrix ");

           // print interchanged matrix

           for (i = 0; i < m; i++) {

               for (j = 0; j < n; j++) {

                   System.out.print(a[i][j] + " ");

               }

               System.out.println("");

           }

       }

       // else block it's only execute when m is not equals

       // to n

       else {

           System.out.println("Rows not equal to columns");

       }

   }

}

Read more about java programming here:

brainly.com/question/18554491

#SPJ1

7 0
1 year ago
Which items are NOT found on a
Alja [10]

Answer:

None of the above cause thats what i put

3 0
2 years ago
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