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masya89 [10]
4 years ago
14

Entropy change is evaluated using Eq. 6.2a based on an internally reversible process. Can the entropy change between two states

of a system be determined for any process linking the two states whether reversible or not?

Engineering
1 answer:
Vadim26 [7]4 years ago
4 0

Answer:

YES

Explanation:

Entropy is an extensive property of the system entropy change that value of entropy change can be determined for any process between the states whether reversible or not. i have attached the formula to calculate entropy change which is independent of whether the system is reversible or not and can be determined for any process.

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Two vehicles arrive at an uncontrolled intersection from different streets at the same time 1.The driver on the right must yield
ss7ja [257]
3. Both vehicles must stop
4 0
3 years ago
A pipeline (NPS = 14 in; schedule = 80) has a length of 200 m. Water (15℃) is flowing at 0.16 m3/s. What is the pipe head loss f
dangina [55]

Answer:

Head loss is 1.64

Explanation:

Given data:

Length (L) = 200 m

Discharge (Q) = 0.16 m3/s

According to table of nominal pipe size , for schedule 80 , NPS 14,  pipe has diameter (D)= 12.5 in or 31.8 cm 0.318 m

We know, head\ loss  = \frac{f L V^2}{( 2 g D)}

where, f = Darcy friction factor

V = flow velocity

g = acceleration due to gravity

We know, flow rate Q = A x V

solving for V

V = \frac{Q}{A}

    = \frac{0.16}{\frac{\pi}{4} (0.318)^2} = 2.015 m/s

obtained Darcy friction factor  

calculate Reynold number (Re) ,

Re = \frac{\rho V D}{\mu}

where,\rho = density of water

\mu = Dynamic viscosity of water at 15 degree  C = 0.001 Ns/m2

so reynold number is

Re = \frac{1000\times 2.015\times 0.318}{0.001}

            = 6.4 x 10^5

For Schedule 80 PVC pipes , roughness (e) is  0.0015 mm

Relative roughness (e/D) = 0.0015 / 318 = 0.00005

from Moody diagram, for Re = 640000 and e/D = 0.00005 , Darcy friction factor , f = 0.0126

Therefore head loss is

HL = \frac{0.0126 (200)(2.015)^2}{( 2 \times 9.81 \times 0.318)}

HL = 1.64 m

7 0
4 years ago
Define factors that can change the performance of a polymer, such are additives
inna [77]

Answer:

 The performance of the polymer is basically change by the various type of factors like shape, tensile strength and color.

The polymer based products are basically influenced by the environmental factors like light, acids or alkalis chemicals, salts and also heat.

The additives is one of the type of chemical polymer which basically include polymer matrix for improving the ability of processing of the polymer. It also helps to enhance the production and requirement of the polymer products in the environment.

8 0
3 years ago
Water is being heated in a closed pan on top of a range whilebeing stirred by a paddle wheel. During the process 30kJ of heat is
My name is Ann [436]

Answer:

38 kJ

Explanation:

The solution is obtained using the energy balance:  

ΔE=E_in-E_out

U_2-U_1=Q_in+W_in-Q_out

U_2=U_1+Q_in+W_in-Q_out

      =38 kJ

4 0
3 years ago
Can anyone help me ?
MrRa [10]
That’s too hard for me lol oof
3 0
3 years ago
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