Entropy change is evaluated using Eq. 6.2a based on an internally reversible process. Can the entropy change between two states
of a system be determined for any process linking the two states whether reversible or not?
1 answer:
Answer:
YES
Explanation:
Entropy is an extensive property of the system entropy change that value of entropy change can be determined for any process between the states whether reversible or not. i have attached the formula to calculate entropy change which is independent of whether the system is reversible or not and can be determined for any process.
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Answer:
28,8 m/s
Explanation:
In a steady flow system we can say that m1=m2 which means that the mass flow in the entrance in the same in the outlet. m is flow (kg/s)
we know that where V (m/s) is velocity, A (m^2) ia area and v is specific volume (m^3/kg)
Since m1=m2 we can say
clearing the equation
we can specific volume (m^3/kg) from thermodynamic tables
for the entrance is 400°C and 4 MPa is superheated steam and v is : 0,7343 m^3/kg
In the outlet we have saturated vapor with quality (x) of 80%. In this case we get the specific saturated volume for the liquid (vf) and the specific volume for the saturated (vg) gas from the thermodynamic tables. we use the next equation to get (v) for the condition of interest, in this case 80% quality.
v= vf +x*(vg - vf)
where:
x: quality
vf = liquid-saturated-specific-volume
vg =steam-saturated-specific-volume.
for this problem
x = 0,8
vf = 0,00102991
vg = 3,24015
so
we get = 2,593 m^3/kg
The area is the one for a circle
r1 = 0,1 m^2 for area 1
r2=0,5 m^2 for area 2
A1 = 0,0314 m^2
A2 = 0,7853 m^2
we know that V1 is 20 m/s
replacing these values in the equation
we get V2 = 28,2 m/s.