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3 years ago

Consider the following statements about weeding and identify the incorrect one.

Chemistry

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

b) Weeding is the process of growing weed

Explanation:

Wedding is an agricultural process carried out to ensure maximum you won't do. It is the process by which weeds i.e. unwanted plants are removed.

As rightly stated in the question;

- Weeding is either done by manual means e.g Cutlasses or use of weedicides, which are chemicals.

- Weeding is best done during tiling operations.

The incorrect option is that "Weeding is the process of growing weed" rather it is a process of removing weed.

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Classify the following mixtures as a 'heterogeneous' or as a 'homogeneous' substance. gasoline [ Select ] soil [ Select ] cranbe

Savatey [412]

The answer is- Gasoline - homogeneous, Soil- heterogeneous, Cranberry juice - homogeneous and Salt water-homogeneous.

Mixture: The substance that has two or more elements or compounds mixed together without binding them chemically is known as mixture.

The constituents of mixture can be separated by various methods.

What are homogeneous and heterogeneous mixture?

Homogeneous mixtures- Homogeneous mixtures are those that have same composition throughout its mass and there are no visible boundaries between its components.

Heterogeneous mixtures- When solute particles are not mixed uniformly in the solvent particles, then a heterogenous mixture is obtained.

Gasoline: It is a homogeneous mixture of various hydrocarbons.
Soil: Soil is a heterogenous mixture and its various components can be seen clearly.
Cranberry juice: It is also a homogeneous mixture as cranberry and water are mixed uniformly.
Salt water is also a homogeneous mixture as salt and water are mixed uniformly.

To learn more about mixtures visit:

brainly.com/question/2849431

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7 0

1 year ago

Read 2 more answers

the quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dis

Basile [38]

Answer:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

Explanation:

At a redox equation, one substance is being oxidized (losing electrons), and the other is being reduced (gaining electrons). In the given reaction:

BrO₃⁻(aq) + Sb³⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq)

When it's at an acidic solution, it must be ions H⁺ on the reactant, which will form water with the oxygen, so the complete reaction is:

BrO₃⁻(aq) + Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq) + H₂O(l)

As we can see, the antimony is being oxidized (go from +3 to +5), and the Bromo is being reduced. The oxidation number of brome in the reactant, knowing that the oxidation number of O is -2, is:

x + 3*(-2) = -1

x = +5

So, it's going from +5 to -1, and the half-reactions are:

BrO₃⁻(aq) + 6e⁻ → Br⁻(aq)

Sb³⁺(aq) → Sb⁵⁺(aq) + 2e⁻

The number of electrons must be the same, so the second equation must be multiplied by 3:

3Sb³⁺(aq) → 3Sb⁵⁺(aq) + 6e⁻

Thus, the equation will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + H₂O(l)

Now, we verify the amount of the elements, which must be equal on both sides. So, we multiply H₂O by 3, and H⁺ by 6, and the balanced reaction will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

6 0

4 years ago

You add 10.0 grams of solid copper(II) phosphate, Cu3(PO4)2, to a beaker and then add 100.0 mL of water to the beaker at T = 298

Natalija [7]

Answer:

1.4×10-37

Explanation:

The equation for the dissolution of the copper II phosphate is first written as shown and the ICE table is set up as also shown. S is obtained as shown and this is now used to obtain 2s and subsequently the solubility product of the calcium phosphate as shown in detail in the image attached to this solution. The step-by-step solution shows how to obtain Ksp when concentration at equilibrium is given.