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kenny6666 [7]
2 years ago
9

Consider the following statements about weeding and identify the incorrect one.

Chemistry
1 answer:
dolphi86 [110]2 years ago
4 0

Answer:

b) Weeding is the process of growing weed

Explanation:

Wedding is an agricultural process carried out to ensure maximum you won't do. It is the process by which weeds i.e. unwanted plants are removed.

As rightly stated in the question;

- Weeding is either done by manual means e.g Cutlasses or use of weedicides, which are chemicals.

- Weeding is best done during tiling operations.

The incorrect option is that "Weeding is the process of growing weed" rather it is a process of removing weed.

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When hno2 dissociates in water, which atom is dontaing electrons, allowing water to act as a lewis base?
miss Akunina [59]

Answer to this is O-atom.

Explanation: The Bronsted acid-base theory is the backbone of chemistry. This theory focuses mainly on acids and bases acting as proton donors or proton acceptors.

A^+ + B^- \rightarrow A-B

where A^+ is the Lewis Acid and B^- is the Lewis Base and A-B is the Covalent Bond.

Reaction of dissociation of HNO2 in H_2O is given as:

HNO_2 + H_2O \rightarrow H_3O^+ + NO_2^-

In this reaction O-atom has lone pair in water and therefore it accepts the proton from HNO_2 forming a Lewis Base.

6 0
3 years ago
Please help ill give brainliest
boyakko [2]

Answer: The answer to the first one is the second option and the answer for the second one is the first option.

Explanation:

5 0
2 years ago
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What two properties most affect the strength of the gravitational forces
goblinko [34]

1) Masses of the object

2) Distance between them

7 0
2 years ago
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5. How many atoms of hydrogen are in a molecule of acetic acid (HC2H202)?
Kazeer [188]

Answer:

in acetic acid ,there are 4 hydrogen atoms

Explanation:

C H 3 C O O H

3 0
3 years ago
Be sure to answer all parts. for each reaction, find the value of δso. report the value with the appropriate sign. (a) 3 no2(g)
Maurinko [17]

Answer:

Change in entropy for the reaction is

ΔS° = -268.13 J/K.mol

Explanation:

To calculate the change in entropy for the balanced reaction, we require the natural entropy of all the reactants and products in the reaction.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

From Literature.

S°(NO₂) = 240.06 J/K.mol

S°(H₂O) = 69.91 J/K.mol

S°(HNO₃) = 155.60 J/K.mol

S°(NO) = 210.76 J/K.mol

These are the entropies of the reactants and products under standard conditions of 298.15 K and 1 atm.

Note that

ΔS° = Σ nᵢS°(for products) - Σ nᵢS°(for reactants)

Σ nᵢS°(for products) = [2 × S°(HNO₃)] + [1 × S°(NO)]

= (2 × 155.60) + (1 × 210.76) = 521.96 J/K.mol

Σ nᵢS°(for reactants) = [3 × S°(NO₂)] + [1 × S°(H₂O)]

= (3 × 240.06) + (1 × 69.91) =790.09 J/K.mol

ΔS° = Σ nᵢS°(for products) - Σ nᵢS°(for reactants)

ΔS° = 521.96 - 790.09 = -268.13 J/K.mol

Hope this Helps!!

4 0
3 years ago
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