Question

Calculate the number of moles of iron (III) oxide (Fe 2 O 3 ) produced from 112 L of oxygen

Answer 1

112 L/ 16 L = 7 mol O2

7 mol O2 x 2 mol Fe2O3/ 3 mol O2 = 4.67 mol Fe2O3

lmk if its right

Answer 2

Answer:

3.33 moles is the required answer.

Explanation:

$4Fe+3O_2\Rightarrow \:2Fe_2O_3$

We're going to use proportion to find the number of moles of iron oxide.

$\frac{\:3\:}{2}\:=\:\frac{\mathrm{Actual\:\text{No}.\:of\:moles\:of\:O_2}}{\mathrm{\text{Actual No}.\:of\:moles\:of\:Fe}_2O_3\:}\:$

Actual no. of moles of oxygen = $\frac{112}{22.4}$   (Since one mole at STP = 22.4 L)

= 5

Putting the values in the proportion.

$\frac{\:3\:}{2}\:=\:\frac{5}{x}\:\\\\x=3.33\:\mathrm{moles\:of\:Fe_2O_3}$

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