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Alexus [3.1K]
3 years ago
8

PLS HELP

Physics
2 answers:
olasank [31]3 years ago
5 0
A, and C hope this helps u out.
RoseWind [281]3 years ago
4 0

Answer:

A and C are correct.

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An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 19 m lower vert
cupoosta [38]

Answer:

The compression in the spring is 5.88 meters.                

Explanation:

Given that,

Mass of the car, m = 39000 kg

Height of the car, h = 19 m

Spring constant of the spring, k=4.2\times 10^5\ N/m

We need to find the compression in the spring in stopping the ore car. It can be done by balancing loss in gravitational potential energy and the increase in elastic energy. So,

mgh=\dfrac{1}{2}kx^2

x is the compression in spring

x=\sqrt{\dfrac{2mgh}{k}} \\\\x=\sqrt{\dfrac{2\times 39000\times 19\times 9.8}{4.2\times 10^5}} \\\\x=5.88\ m

So, the compression in the spring is 5.88 meters.                                                                                                                  

6 0
3 years ago
Why is there zero current when a light bulb burns out?
kozerog [31]

The circuit is no longer closed.

8 0
4 years ago
The velocity v(t) in the table below is increasing for 0_t_12.
katen-ka-za [31]
<span>When n=4 subdivisions distance traveled = 40 X 12 = 480

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7 0
4 years ago
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If the net torque is zero, what does this imply about the clockwise and counterclockwise torques.
lapo4ka [179]

Answer:

Explanation:

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7 0
3 years ago
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