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Paraphin [41]
3 years ago
8

What happens to the force between the objects if Mass 2 decreases? (increases, decreases

Physics
1 answer:
Anna35 [415]3 years ago
6 0
The more separation two objects have, the more the force between them decreases. When mass 1 increases the force between the objects increases. If Mass 2 decreases, the force between the objects decreases.
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A uniform beam resting on two pivots has a length L = 6.00 m and weight M = 220 lbs. The pivot under the left end exerts a norma
gulaghasi [49]

Answer:

x = 4,138 m

Explanation:

For this exercise, let's use the rotational equilibrium equation.

Let's fix our frame of reference on the left side of the pivot, the positive direction for anti-clockwise rotation

         ∑ τ = 0

         n₁ 0 - W L / 2 + n₂ 4 - W_woman  x = 0

         x = (- W L / 2 + 4n2) / W_woman

Let's reduce the magnitudes to the SI System

         M = 6 lbs (1 kg / 2.2 lb) = 2.72 kg

         M_woman = 130 lbs = 59.09 kg

Let's write the transnational equilibrium equation

         n₁ + n₂ - W - W_woman = 0

         n₁ + n₂ = W + W_woman

        n₁ + n₂ = (2.72 + 59.09) 9.8

At the point where the system begins to rotate, pivot 1 has no force on it, so its relation must be zero (n₁ = 0)

          n₂ = 605,738 N

 

Let's calculate

         x = (-2.72 9.8 6/2 + 4 605.738) / 59.09 9.8

         x = 4,138 m

4 0
4 years ago
I will fan and give 2 medals!!!!!!
Maksim231197 [3]
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<span>I.                  </span>Rare gaseous envelope

<span>II.              </span>Irregular pearly glow

<span>III.          </span>Total solar eclipse

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<span>V.                 </span>Caused by diffraction

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<span>II.              </span>large bright gaseous

<span>III.          </span>luminous hydrogen gas

<span>IV.             </span>rises above chromospheres

<span>V.                 </span>anchored to surface (sun’s surface)

<span> Solar Flare </span>

<span>I.                  </span>Intense High-energy

<span>II.              </span>Causes electromagnetic disruptions

<span>III.          </span>In solar atmosphere

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<span>V.                 </span>Emits radiation 

<span> Sunspots </span>

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7 0
3 years ago
A wire carrying a 29.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's
Dmitrij [34]

Answer:

2.59 T

Explanation:

Parameters given:

Current flowing through the wire, I = 29 A

Angle between the magnetic field and wire, θ = 90°

Magnetic force, F = 2.25 N

Length of wire, L = 3 cm = 0.03 m

The magnetic force, F, is related to the magnetic field, B, by the equation below:

F = I * L * B * sinθ

Inputting the given parameters:

2.25 = 29 * 0.03 * B * sin90

2.25 = 0.87 * B

=> B = 2.25/0.87

B = 2.59 T

The magnetic field strength between the poles is 2.59 T

4 0
3 years ago
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