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Naddika [18.5K]
3 years ago
13

Which type of change does the statement describe? Someone help fast

Chemistry
1 answer:
grandymaker [24]3 years ago
7 0

Explanation:

bottom right = physical change

top left = chemical change

top right = physical change

bottom left = chemical change

<h3>A physical change is a change that goes from one form to another and physical changes can be reversed</h3><h3>example: water to ice or air to water</h3><h3 /><h3>A chemical change is when a substance combines with another substance and when it is combined it cannot be reversed</h3><h3>example: burning and or rusting</h3>

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Fireworks exploding in the sky and giving off light are an example of a(n) _____.
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- This wouldn't be a physical change, but instead a chemical change. A clue that it is a chemical change is that energy was given off.
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3 years ago
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3 years ago
The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to
tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


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3 years ago
Draw the structure(s) of all of the possible monochloro derivatives of 2,4-dimethylpentane, c7h15cl.
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The monochloroderivatives will be obtained by substituting chemically non equivalent hydrogen with chlorine atom, one by one

So the possible monochloro derivatives of 2,4-dimethylpentane (figure 1) are shown in figure (2)




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3 years ago
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