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Nadya [2.5K]
4 years ago
15

A well-insulated cup of water is too hot to make tea, so you mixed it with an equal amount of cool water to lower the temperatur

e. The temperature of the mixture is exactly the midpoint between the temperature of the hot and cool water. What is the entropy change of the system consisting of the total amount of water
Chemistry
1 answer:
natulia [17]4 years ago
4 0

Answer:

The entropy of the final solution decreases, as the reaction disorder is less.

Explanation:

The higher the temperature, the greater the heat of the reaction and the greater the disorder it has, so the entropy will increase ... But this is not the case, since the solution cools, decreasing the entropy proportionally.

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State the relationship between phase changes and heat energy.<br> In complete sentences
Harman [31]
Changes in phase from solid to liquid (melting) and from liquid to gas (boiling) require energy. When solid ice melts and becomes a liquid, the particles of the substance move farther apart and heat energy is gained. When water boils, if forms steam (a gas).
8 0
3 years ago
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The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

\log D=\log D_o-\frac{E_a}{2.303RT}

where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K

Hence, the temperature of the system will be 1622 K

8 0
3 years ago
Can someone explain compressibility please ?
RUDIKE [14]
Compressibility refers to the amount or extent to which a substance can be compressed, also involving the the relationship between changes in volume due to applied pressure.
6 0
3 years ago
Converting the following mm Hg (torr) to standard
11Alexandr11 [23.1K]

Explanation:

Given:

20.5 torr

78.6 torr

225 torr

Change into atm

Computation:

We know that;

1 torr = 0.00131579 atm

So,

1. 20.5 torr

= 20.5 x 0.00131579 atm

= 0.02697

= 0.027 atm (Approx)

2. 78.6 torr

= 78.6 x 0.00131579 atm

= 0.103090

= 0.103 atm (Approx)

3. 225 torr

= 225 x 0.00131579 atm

= 0.2960

= 0.296 atm (Approx)

5 0
3 years ago
a 20.4 g aluminum sphere and a 49.4 g iron sphere are both added to 75.2 mL of water contained in a graduated cylinder. what is
alexandr1967 [171]
The level in the beaker will increase because the volumes of the spheres will also be added to the volume of the water. First, we must determine the volume of each sphere. For this, we will use:

density = mass / volume
We can check the density of both aluminum and iron in literature, and given the mass, we may obtain the volume. 

Aluminum:
Density = 2.70 g/ml
Mass = 20.4 g
Volume = 20.4 / 2.7 = 7.56 ml


Iron:
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Now, we add these volumes to the volume of water present:
75.2 + 6.28 + 7.56 = 89.04

The new level will be 89.0 ml
3 0
3 years ago
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