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Nadya [2.5K]
3 years ago
15

A well-insulated cup of water is too hot to make tea, so you mixed it with an equal amount of cool water to lower the temperatur

e. The temperature of the mixture is exactly the midpoint between the temperature of the hot and cool water. What is the entropy change of the system consisting of the total amount of water
Chemistry
1 answer:
natulia [17]3 years ago
4 0

Answer:

The entropy of the final solution decreases, as the reaction disorder is less.

Explanation:

The higher the temperature, the greater the heat of the reaction and the greater the disorder it has, so the entropy will increase ... But this is not the case, since the solution cools, decreasing the entropy proportionally.

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If 20.0 grams of Na reacts with 30.0 gtams of Cl2 what mass of NaCl is produfed by the reaction
IgorLugansk [536]

Answer:

mNaCl = mNa + mCl

mNa = 20g

mCl = mCl2/2 = 30/2 = 15g

mNaCl= 20+15 = 35g

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ACTUAL YIELD VS THEORETICAL YIELD?
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Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H20
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A. 1350

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Determine the the mass of one molecule of hydrogen sulfide gas.
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the molecular mass of hydrogen sulphide, which contains two atoms of hydrogen and one atom of sulphur is = 2 — 1 + 1 — 32 = 34 a.m.u.

6 0
3 years ago
Calculate the moles of calcium oxalate formed from 5 grams of potassium oxalate (molar mass 184.24 g/mol) the mole mole ratio fr
Nataly_w [17]

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).

We can calculate the moles of CaC₂O₄ obtained considering the following relationships.

  • The molar mass of K₂C₂O₄ is 184.24 g/mol.
  • The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

5 g K_2C_2O_4 \times \frac{1molK_2C_2O_4}{184.24gK_2C_2O_4}  \times \frac{1molCaC_2O_4}{2molK_2C_2O_4} = 0.03molCaC_2O_4

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Learn more: brainly.com/question/15288923

7 0
2 years ago
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