Did the strongman pull up or push down to lift the pig

A slinky is stretched by two forces. When the forces are removed, the slinky returns to its original length. The slinky has been

e-lub [12.9K]

Answer: elastically deformed or non-permanently deformed

Explanation:

According to classical mechanics, there are two types of deformations:

-Plastic deformation (also called irreversible or permanent deformation), in which the material does not return to its original form after removing the applied force, therefore it is said that the material was permanently deformed.

This is because the material undergoes irreversible thermodynamic changes while it is subjected to the applied forces.

-Elastic deformation (also called reversible or non-permanent deformation), in which the material returns to its original shape after removing the applied force that caused the deformation.

In this case the material also undergoes thermodynamic changes, but these are reversible, causing an increase in its internal energy by transforming it into elastic potential energy.

Therefore, the situation described in the question is related to elastic deformation.

8 0

3 years ago

Find the magnitude of the electric field due to a charged ring of radius "a" and total charge "Q", at a point on the ring axis a

34kurt

Answer:

E= $\frac{KQ}{2\sqrt 2a^2}$

Explanation:

We are given that

Charge on ring= Q

Radius of ring=a

We have to find the magnitude of electric filed on the axis at distance a from the ring's center.

We know that the electric field at distance x from the center of ring of radius R is given by

$E=\frac{kQx}{(R^2+x^2)^{\frac{3}{2}}}$

Substitute x=a and R=a

Then, we get

$E=\frac{KQa}{(a^2+a^2)^{\frac{3}{2}}}$

$E=\frac{KQa}{(2a^2)^{\frac{3}{2}}}$

$E=\frac{KQa}{2\sqrt 2a^3}$

$E=\frac{KQ}{2\sqrt 2a^2}$

Where K= $9\times 10^9 Nm^2/C^2$

Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center= $\frac{KQ}{2\sqrt 2a^2}$

4 0

3 years ago

Help Why does the sun move around the Milky Way galaxy

AnnyKZ [126]

It doesn't the sun stays still we move around the sun

5 0

3 years ago

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Do balanced forces change an objects motion

meriva

If the group of all forces acting on an object is balanced,
then the effect of all of them is the same as if there were
no forces at all on the object. In that case, the object
continues moving in a straight line at a constant speed.

8 0

3 years ago

Avi, a gymnast, weighs 40 kg. She is jumping on a trampoline that has a spring constant value of 176,400 . If she compresses the

viva [34]

Answer

9 m

Explanation

The energy stored in a spring is given by:

Energy = 1/2 k²e

Where e is the compression and k is the spring constant.

Energy = 1/2 × 176,400 × 0.2²

= 3,528 N

The same energy will then be converted to potential energy given by:

Energy = mgh

Where m is the mass, g is the gravity and h is the height above the ground.

Energy = mgh

3,528 = 40 × 9.8 × h

3,528 = 392h

h = 9 m

3 0

3 years ago

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