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2 years ago

7

Use the bar graph to find the experimental probability of the event

1 answer:

Alexeev081 [22]2 years ago

5 0

First add up the number of times spun. We get 50 spins now add up the number of spins that we didn't get 1. For that we get 42 now divide 42/50= 21/25. So for every 25 spins 21 of them will probably be something other than 1. Your answer is 21/25

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Please solve fast. Q.No. 26 and 29.<br>26. x²+5x+25/4<br>27. x²/4y²-2/3+4y²/9x²

Usimov [2.4K]

Step-by-step explanation:

26. x²+5x+25/4 = (x + 5/2)²

29. x²/4y²-2/3+4y²/9x² = (x/2y - 2y/3x)²

6 0

2 years ago

Read 2 more answers

PLZ HELP!!!!!! I THINK ITS TRUE BUT IM NOT SURE

suter [353]

Yes it is true! it is true because two different numbers go to the same number, if it was false it would have to be the one number to two different numbers.

Hope that made sense!

5 0

3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!

castortr0y [4]

Answer:

$3.75

Step-by-step explanation:

dimes= x

quarters= x+2

nickels= 2x+2

sum is 3.75

.10x+.25(x+2)+0.05(2x+2)=3.75

.10x+.25x+.50+0.10x+0.10=3.75

0.45x=3.15

x=7 dimes (0.70)

x+2=9 quarters (2.25)

2x+2=16 nickels (0.80)

They add to $3.75

5 0

2 years ago

Read 2 more answers

The radius of the circle - shaped poster is 9 inches. What is the approximate circumference?

statuscvo [17]

Answer: $56.55inch$

Step-by-step explanation:

Circumference formula: $C = 2\pi r$

$C = 2(3.1416)(9inch)$

$C= 56.55inch$

5 0

3 years ago

Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.

Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

$f(z_n)={z_{n-1}} ^2+c$

Given that:

$\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i$

The first iterate will be:

$\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}$

The second iterate will be:

$\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}$

And the third iterate will be:

$\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}$

Hence, our answer is C.

3 0

2 years ago