Answer and Explanation:
Cup 1. The ice cubes are in a solid state.
Cup 2: The cup has water that is liquified.
Cup 3: The cup is empty and only contains free floating air particles.
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Answer:
Resistance of the second wire is twice the first wire.
Explanation:
Let us first see the formula of resistance;
R = pxL/A
Here L is the lenght of the wire, A the area and p is the resistivity of wire.
As we are given that the length of second wire is double than that of the first wire, hence the resistance of second wire would be double.
Since we have two loop in second case, inducing double voltage but as resistance is doubled so the current would remain same according to ohms law
I = V/R
To what i see, the answer is....
C.
This is an example of conduction
(a) Zero
The maximum efficiency (Carnot efficiency) of a heat engine is given by
where
is the low-temperature reservoir
is the high-temperature reservoir
For the heat engine in the problem, we have:
Therefore, the maximum efficiency is
(b) Zero
The efficiency of a heat engine can also be rewritten as
where
W is the work performed by the engine
is the heat absorbed from the high-temperature reservoir
In this problem, we know
Therefore, since the term cannot be equal to infinity, the numerator of the fraction must be zero as well, which means
W = 0
So the engine cannot perform any work.
