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3 years ago

My sis needs help with this and I don't wanna help her!!! Can you guys help her????

Physics

2 answers:

Katena32 [7]3 years ago

7 0

Answer and Explanation:

Cup 1. The ice cubes are in a solid state.

Cup 2: The cup has water that is liquified.

Cup 3: The cup is empty and only contains free floating air particles.

***If you found my answer helpful, please give me the brainliest. :) ***

VikaD [51]3 years ago

7 0

The first cup has ice cubes. When water freezes it expands. The ice is solid.
The second cup has water.
The third cup is empty.

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Answer:

The first one (60%)

Explanation:

The first one converts 15% more energy than the other one. Therefore, it is more efficient.

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scZoUnD [109]

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A unit mass of an ideal gas at temperature T undergoes a reversible isothermal process from pressure P1 to pressure P2 while los

mafiozo [28]

Answer:

Option B

Change in entropy of the process is $\Delta S= Rln(\frac{P_{1}}{P_{2}})$

Explanation:

The entropy of a system is a measure of the degree of disorderliness of the system.

The entropy of a system moving from process 1 to 2 is given as

$\Delta S = \int\limits^2_1 {\frac{\delta q}{T}}$

recall from first law, $\delta q =du +Pdv$

hence we have, $\Delta S = \int\limits^2_1 {\frac{du +Pdv}{T}}$

since the process is isothermal, $du= 0$

this gives us $\Delta S = \int\limits^2_1 {\frac{Pdv}{T}}$

integrating within the limits of 1 and 2, will give us

$\Delta S = R ln (\frac{V_{2}}{V_{1}})$

also from ideal gas laws,

$\frac{V_{2}}{V_{1}}=\frac{P_{1}}{P_{2}}$

hence we have $\Delta S = R ln (\frac{P_{1}}{P_{2}})$

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Answer:

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cosmic microwave background radiation

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