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3 years ago

How is velocity and momentum related?

Physics

1 answer:

Scrat [10]3 years ago

8 0

Answer:

(The momentum of an object is equal to the mass of the object times the velocity of the object.) ★Where m is the mass and v is the velocity. The equation illustrates that momentum is directly proportional to an object's mass and directly proportional to the object's velocity.

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How is newtons third law of motion demonstrated on a roller coaster?

butalik [34]

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3 years ago

A boat having stones floats in water. If stones are unloaded in water, what will happen to the level of water?

Pani-rosa [81]

Explanation:

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3 years ago

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3 years ago

Read 2 more answers

Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.

alexandr1967 [171]

Answer:

$v=\sqrt{k\frac{e^2}{m_e r}}$ , $2.18\cdot 10^6 m/s$

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

$k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}$

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

$m_e$ is the mass of the electron

Solving for v, we find

$v=\sqrt{k\frac{e^2}{m_e r}}$

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

$r=5.3\cdot 10^{-11}m$

while the electron mass is

$m_e = 9.11\cdot 10^{-31}kg$

and the charge is

$e=1.6\cdot 10^{-19} C$

Substituting into the formula, we find

$v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s$

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3 years ago

8. Two forces of 10 N and 30 N are applied to a 10 kg box. Find (1) the box’s acceleration when both forces point due east and (

love history [14]

(1) acceleration, a = 4 m/ $s^{2}$ (2) acceleration of 10 N, $a_{1}$ = 1 m/ $s^{2}$ and acceleration of 30 N, $a_{2}$ = 3 m/ $s^{2}$

Explanation:

Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
Let $a_{1}$ be the acceleration for force 10 N, to find acceleration rearrange the equation to a = $\frac{F}{m}$ . When we substitute 10 N force and 10 kg mass of the box in the equation. We will get $a_{1}$ = 1 m/ $s^{2}$

Let $a_{2}$ be the acceleration for force 30 N, to find acceleration rearrange the equation to F = $\frac{F}{m}$ . When we substitute 30 N force and 10 kg mass of the box in the equation. We will get $a_{2}$ = 3 m/ $s^{2}$
To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/ $s^{2}$

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3 years ago