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2 years ago

How is velocity and momentum related?

Physics

1 answer:

Scrat [10]2 years ago

8 0

Answer:

(The momentum of an object is equal to the mass of the object times the velocity of the object.) ★Where m is the mass and v is the velocity. The equation illustrates that momentum is directly proportional to an object's mass and directly proportional to the object's velocity.

You might be interested in

A force which resist the relative motion of two bodies in direct contact is called _______

Elena-2011 [213]

Frictional Force is the answer..

Hope it helps

3 0

3 years ago

calculate the work done in kilo joules in lifting a mass of 20kg at steady velocity through a vertical height of 20m

bulgar [2K]

Answer:

$\huge\boxed{\sf Work\ done = 4 kJ}$

Explanation:

Since work done is in the form of potential energy, we will use the formula of potential energy here.

We know that,

Where,

m = mass = 20 kg

g = acceleration due to gravity = 10 m/s²

h = vertical height = 20 m

So,

Work done = (20)(10)(20)

Work done = 4000 joules

Work done = 4 kJ

$\rule[225]{225}{2}$

5 0

1 year ago

A pencil sharpener has a handle with a radius of 1.5 cm. The sharpening mechanism has a radius of 0.5 cm. What is the IMA of the

abruzzese [7]

1.5 / 0.5 = 3 I believe this is the right answer

8 0

3 years ago

In 1-2 sentences explain how you would determine the constant k for a spring.

Dmitrij [34]

To perform an experiment to determine the force constant of a spring, you will need a stand with a boss and clamp, a spiral spring, a meter rule and different weights.

The setup is arranged as shown in the image attached. The natural length of the spring is first recorded. Different weights are added to the spring one after the other and the extension is recorded.

The weight is now plotted on the vertical axis and the extension is plotted on the horizontal axis. The slope of the graph is the force constant of the spring.

Learn more: brainly.com/question/10991960

3 0

2 years ago

A new mechanic foolishly connects an ammeter with 0.1 Ω resistance directly across a 12-V car battery with internal resistance o

NemiM [27]

Answer:

The power dissipated by the meter is 1188W

Explanation:

Here we have a circuit constituted with a power source and two resistors in series, we can calculate the power dissipated by the meter using the following formula:

$P=I^2R_m$

We first need to fin the current going through the circuit:

$I=\frac{V}{R}\\where:\\V=voltage\\R=resistance$

$R=R_s+R_m$

because they are connected in series. So:

$I=\frac{12V}{(0.01+0.1)}=109A$

$P=(109)^2*0.1=1188W$

8 0

2 years ago