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Len [333]
3 years ago
13

A marble block has dimensions of 0.4m x 0.4m x 2m. Knowing that the density of marble is 2,400 kg / m3, calculate the mass of th

e block and answer:
Um bloco de mármore tem dimensões 0,4m x 0,4m x 2m. Sabendo que a densidade do mármore é 2 400 kg/m3, calcule a massa do bloco e responda:
Physics
1 answer:
Ostrovityanka [42]3 years ago
4 0
So to find the mass we must use the formula D=M/V but because we don’t have the mass, we must use the formula M=DxV

So to find volume, just multiple the length (0.4m) width (0.4m) and height (2m) and you will get 0.32m as the volume. Now multiple this volume with your given density of 2,400 kg/m and you will get 768 kg as the mass of the marble block.

Final answer: 768 kilograms (kg) as mass of the marble block.
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The intensity of the radiation from the Sun measured on Earth is 1360 W/m2 and frequency is f = 60 MHz. The distance between the
Mama L [17]

Answer: (a) power output = 3.85×10²⁶W

(b). There is no relative change in power as it is independent from frequency

(c). 590 W/m²

Explanation:

given Radius between earth and sun to be = 1.50 × 10¹¹m

Intensity of the radiation from the sun measured on earth to be = 1360 W/m²

Frequency = 60 MHz

(a). surface area A of the sun on earth is = 4πR²

substituting value of R;

A = 4π(.50 × 10¹¹)² = 2.863 10²³×m²

A = 2.863 10²³×m²

now to get the power output of the sun we have;

<em>P </em>sun = <em>I </em><em>sun-earth </em><em>A </em><em>sun-earth</em>

where A = 2.863 10²³×m², and <em>I </em> is 1360 W/m²

<em>P </em>sun =  2.863 10²³ × 1360

<em>P </em>sun = 3.85×10²⁶W

(c). surface area A of the sun on mars is = 4πR²

now we substitute value of 2.28 ×10¹¹ for R sun-mars, we have

A sun-mars = 4π(2.28× 10¹¹)²

A sun-mars = 6.53 × 10²³m²

now to calculate the intensity of the sun;

<em>I </em><em>sun-mars = </em><em>P </em>sun / A sun-mars

where <em>P </em>sun = 3.85×10²⁶W and A sun-mars = 6.53 × 10²³m²

<em>I </em><em>sun-mars =  </em>3.85×10²⁶W / 6.53 × 10²³m²

<em>I </em><em>sun-mars = </em>589.6 ≈ 590 W/m²

<em>I </em><em>sun-mars = </em>590 W/m²

6 0
3 years ago
Which of the following quantities are vectors?
Arte-miy333 [17]

Answer:

electric fields

Explanation:

3 0
3 years ago
A top is a toy that is made to spin on its pointed end by pulling on a string wrapped around the body of the top. The string has
AlladinOne [14]

Given Information:

Angular displacement = θ = 51 cm = 0.51  m

Radius = 1.8 cm = 0.018 m

Initial angular velocity = ω₁ = 0 m/s

Angular acceleration = α = 10 rad/s ²

Required Information:

Final angular velocity = ω₂ = ?

Answer:

Final angular velocity = ω₂ = 21.6 rad/s

Explanation:

We know from the equations of kinematics,

ω₂² = ω₁² + 2αθ

Where ω₁ is the initial angular velocity that is zero since the toy was initially at rest, α is angular acceleration and θ is angular displacement.

ω₂² = (0)² + 2αθ

ω₂² = 2αθ

ω₂ = √(2αθ)

We know that the relation between angular displacement and arc length is given by

s = rθ

θ = s/r

θ = 0.51/0.018

θ = 23.33 radians

finally, final angular velocity is

ω₂ = √(2αθ)

ω₂ = √(2*10*23.33)

ω₂ = 21.6 rad/s

Therefore, the top will be rotating at 21.6 rad/s when the string is completely unwound.

3 0
3 years ago
In nineteenth century, physical science was divided into discipline. . ​
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Answer:

Here! Try this Website!: www.britannica.com › science › physical-science physical science | Definition, History, & Topics | Britannica. So you will learn a lot more about science, history, and topics about it!

8 0
2 years ago
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What statement best describes what it means to maximize your efforts in sports?
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What statement best describes what it means to maximize your efforts in sports?

D.none of the above

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