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Semmy [17]
3 years ago
14

I NEED HELP WIT MY SCIENCE GIZMO PAGE 4 QUESTION 3 THIS IS ALREADY LATE SO I NEED HELPPPP!!!!!!

Chemistry
1 answer:
algol [13]3 years ago
3 0
Sorry i need the points but if i knew the answer i’ll tell you sorry
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In an exothermic process the surrounding looses heat.<br>False<br>True<br>​
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Answer:

False

Explanation:

In an exothermic process, the reaction gives off heat, and not takes it in.  If it takes it in from the surroundings, then it would be endothermic.

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Is condensation an exothermic or endothermic process? Based on Le Cha^telier’s principle, would you predict the vapor pressure o
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Explanation:

A process in which water vapor changes into liquid state is known as condensation. As we know that when energy is released in a reaction then it is known as exothermic reaction and when energy is absorbed in a reaction then it is known as endothermic reaction.

As vapors have high energy so, when they change into liquid state then heat energy is released by them. Therefore, condensation is an exothermic reaction.

As per Le Chatelier's principle, any disturbance caused in an equilibrium reaction will tend to shift the equilibrium in a direction away from the disturbance.

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How many electrons will be in the valence of non- H atoms when they make covalent bonds?
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The salt used to malt snow on a walkway outside a house is calcium chloride and is sold in 20kg bags. How many molecules of calc
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4 years ago
A student has a mixture of salt (NaCl) and sugar (C12H22O11). To determine the percentage, the student measures out 5.84 grams o
julsineya [31]

Answer:

The volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml

Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

Number \, of \, moles, n  = \frac{Mass}{Molar \ mass} =  \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl

0.09993 moles of NaCl will react with 0.09993 moles of AgNO₃

Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

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4 years ago
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