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Alekssandra [29.7K]
3 years ago
13

Game officials are accepted as the rule experts for any competition they oversee. true or false

Physics
1 answer:
Nat2105 [25]3 years ago
8 0

Answer:

True

Explanation:

I Got It Right On Edge :)

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As light slows down, it bends or refracts. The index of refraction helps predict the amount of bending. How are the speed of lig
Eduardwww [97]
When light changes the medium it travels through it also changes speed. The speed in medium is given by formula:
v_{medium} = \frac{c}{ n_{medium} }

Rearranging formual gives:
n_{medium} = \frac{c}{ v_{medium} }

From this formula we can make conclusion that index of refraction is inversely proportional to speed of light in medium. This means that greater speed gives smaller index of refraction.
8 0
4 years ago
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Mary is an avid game show fan and one of the contestants on a popular game show. She spins the wheel, and after 5.5 revolutions,
spin [16.1K]

Answer:

The angle is 23.2 radians, equivalent to 3.69 revolutions.

Explanation:

First, we need to find the angular acceleration of the wheel. This can be done using one of the kinematic formulas:

\omega^{2}=\omega_0^{2}+2\alpha\theta\\\\\implies \alpha=\frac{\omega^{2}-\omega_0^{2}}{2\theta}

Since the final angular velocity is zero after 5.5 revolutions (equivalent to 11π radians) we have that:

\alpha=\frac{-(3.15rad/s)^{2}}{2(11\pi rad)}\\\\\alpha=-0.144rad/s^{2}

Now, using the same equation, we can solve for the requested angle:

\theta=\frac{\omega^{2}-\omega_0^{2}}{2\alpha}\\\\\theta=\frac{(1.80rad/s)^{2}-(3.15rad/s)^{2}}{2(-0.144rad/s^{2})}\\\\\theta=23.2rad

Finally, it means that the angle through which the wheel has turned when the angular speed reaches 1.80 rad/s is 23.2 radians, equivalent to 3.69 revolutions.

8 0
3 years ago
How should you move a bar magnet to cause an electric current to flow in a
Nostrana [21]

I got A it was the same question to. Guess its a different answer for every one

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3 years ago
14 km equals how much meters
MrRa [10]
14 km equals 14,000 metres
6 0
3 years ago
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What is the approximate diameter of an inflated
forsale [732]
Well let's convert all these values out of standard form first:

2x10^-2 = 2x0.01 = 0.02m = 2cm
2x10^0m = 2x1 = 2m
2x10^-1m = 2x0.1 = 0.2m = 20cm
2x10^1m = 2x10 = 20m

Based on that, we know that 20cm is roughly equivalent to a basketball (at least it's closer than all the other values), so the answer is therefore 2 - 2x10^-1m
6 0
3 years ago
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