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Leona [35]
3 years ago
8

A car is traveling at an angular acceleration of 0.04 rad/s2 on a circular part of a road. If the radius of the circular part is

200m, find the net acceleration of the car when the angular velocity of the car is 0.2rad/s.
Physics
1 answer:
natta225 [31]3 years ago
4 0

Answer:

8 m/s²

Explanation:

α = 0.04 rad/s²

w = 0.2 rad/s

t = ?

α = w/t

===> t = w/α = 0.2/0.04 = 5 sec

v = wr = 0.2 × 200 = 40 m/s

the net acceleration a = v/t = 40/5 = 8 m/s²

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klio [65]

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is 9 \times 10^{-4} m^{2}. As the capacitance of capacitor is given as follows.

            C = \frac{\epsilon_{o}A}{d}

It is known that the dielectric strength of air is as follows.

               E = 3 \times 10^{6} V/m

Expression for maximum potential difference is that the capacitor can with stand is as follows.

                       dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

               Q = CV

                   = \frac{\epsilon_{o} A}{d} \times E \times d

                   = \epsilon_{o}AE

                   = 8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}

                   = 1.062 \times 10^{-8} C

or,                = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

5 0
3 years ago
A football is thrown at an initial velocity of 51 mph at an angle of 37 degrees. How many yards is the football thrown
Allisa [31]

Answer:250.03m

Explanation:

Initial velocity =u=51mph

Angle=β=37

Acceleration due to gravity=g=10

The distance covered by the football is the range

Range=(u^2xsin2β)/g

Range=(51^2xsin(2x37))/10

Range=(51x51xsin74)/10

Range=(2601xsin74)/10

Range=(2601x0.9613)/10

Range=(2500.3)/10

Range=250.03m

3 0
3 years ago
Consider two copper wires of equal cross-sectional area. One wire has 3 times the length of the other. How do the resistivities
vladimir2022 [97]

Answer:

Both wires have the same resistivity.

Explanation:

The resistivity of a material depends on the following factors:

  1. The nature of the material, i.e., the number density of free electrons of the material.
  2. The temperature of the material.

The resistance R of a wire of resistivity \rho, length l and cross-sectional area A is given by

R=\dfrac{\rho l}{A}.

On varying the length and cross-sectional area of the wire, the resistance of the wire is changed but resistivity does not change as it is an intrinsic property of the material of the wire.

For the two given wires, the length and the cross-sectional area are different, but both the wires are of copper which means the number density of free electrons on both the wires is same and both the wires are placed in same environmental condition, which means the temperature would also be same.

Thus, the resistivities of both the wire are same.

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3 years ago
Demaryius Thomas (104.0 kg) jumps up 75 cm and then runs down the field at 5.10 m/s.
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Answer:

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Answer:

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3 years ago
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