Answer: 3/4 i think
Step-by-step explanation:
Answer:
466mEq
Step-by-step explanation:
First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):
So, we have 27000mg in 3L of normal saline solution.
Now, acording to our milliequivalent (mEq) equation (
) where pE is de molecular mass of NaCl divided by their charges, in this case 1:
Finally we substitute in the mEq formula:
I hope you find this information useful! Good luck!
Answer:
x = friends that paid discount price = 8
y = friends that paid regular price = 4
Step-by-step explanation:
Let
x = friends that paid discount price
y = friends that paid regular price
x + y = 12 (1)
6x + 8y = 80 (2)
From (1)
x = 12 - y
Substitute x = 12 - y into (2)
6x + 8y = 80 (2)
6(12 - y) + 8y = 80
72 - 6y + 8y = 80
- 6y + 8y = 80 - 72
2y = 8
y = 8/2
y = 4
Substitute y = 4 into (1)
x + y = 12 (1)
x + 4 = 12
x = 12 - 4
x = 8
x = friends that paid discount price = 8
y = friends that paid regular price = 4
this is a question from me to you not an answer sorry what class are you taking
