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charle [14.2K]
3 years ago
7

What is the mean distance between the Sun and the core of the Milky Way?

Physics
1 answer:
sertanlavr [38]3 years ago
4 0

Answer:

about 8 kpc

Explanation:

You might be interested in
Charlie Brown kicks a football at 24.5 m/s at 35.0. What is the maximum height of the ball?
lozanna [386]

Answer:

d = 10.076 m

Explanation:

We need to obtain the velocity of the ball in the y direction

Vy  = 24.5m/s * sin(35) = 14.053 m/s

To obtain the distance, we use the formula

vf^2 = v0^2 -2*g*d

but vf = 0

d = -vo^2/2g

d = (14.053)^2/2*(9.8) = 10.076 m

5 0
3 years ago
Write the formula of Lever, Pulleys, wheel and axle and inclined plane.<br>​
maxonik [38]

Answer:

Lever => d_{e} = d_{r}

Pulley => G = M x n (gravitational acceleration)

Wheel and axle => M.A = Radius of the wheel/radius of the axle = R/r

Inclined plane => It can be divided into two components: Fi = Fg * sinθ - parallel to inclined plane. Fn = Fg * cosθ - perpendicular one.

6 0
2 years ago
Which term, taken from the celestial sphere, gives its name to a.m. and p.m.?
DaniilM [7]

Options are. Zenith, Great circle, Equinox, or Meridan
3 0
2 years ago
Suppose the electrostatic force between two electrons is F. What is the electrostatic force between an electron and a proton
mars1129 [50]

Answer:

D. −F

Explanation:

the rest of the answers are

2/3F

The force is represented as a positive quantity and is repulsive.

Electrostatic force is inversely proportional to the square of the distance.

The direction of the force changes, and the magnitude of the force quadruples.

hope this helps sorry if i was too late! :)

8 0
3 years ago
A metal cube with sides of length a=1cm is moving at velocity v0→=1m/sj^ across a uniform magnetic field B0→=5Tk^. The cube is o
Nitella [24]

Answer:

the magnitude of the electric field is 1.25 N/C

Explanation:

The induced emf in the cube ε = LB.v where B = magnitude of electric field = 5 T , L = length of side of cube = 1 cm = 0.01 m and v = velocity of cube = 1 m/s

ε = LB.v = 0.01 m × 5 T × 1 m/s = 0.05 V

Also, induced emf in the cube ε = ∫E.ds around the loop of the cube where E = electric field in metal cube

ε = ∫E.ds

ε = Eds since E is always parallel to the side of the cube

= E∫ds  ∫ds = 4L since we have 4 sides

= E(4L)

= 4EL

So,4EL = 0.05 V

E = 0.05 V/4L

= 0.05 V/(4 × 0.01 m)

= 0.05 V/0.04 m

= 1.25 V/m

= 1.25 N/C

So, the magnitude of the electric field is 1.25 N/C

7 0
2 years ago
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