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Elanso [62]
2 years ago
11

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t

he axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 1.3 m long, and the nerve impulse speed is 33 m/s, how long (in s) does it take for the nerve signal to travel this distance?
Physics
1 answer:
zysi [14]2 years ago
3 0

Answer:

Explanation:

Speed of electrical nerve signal = 33 m /s

Distance travelled = 1.3 m

time taken = distance / speed

= 1.3 / 33  

= .039 s

= 39 ms ( millisecond )  .

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3 years ago
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Explanation:

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kompoz [17]

Answer:

0.5 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

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Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

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u is the initial velocity.

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With the above formula, we can obtain the acceleration of the car as follow:

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Time (t) = 20 s

Acceleration (a) =?

a = (v – u) / t

a = (10 – 0) / 20

a = 10/20

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6 0
2 years ago
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kotegsom [21]
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3 years ago
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ddd [48]

Answer:

D

Explanation:

5 0
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