Answer:
a) 2.85 m/s
b) -24.01 m/s
c) 1
Explanation:
From the question, we can attest that the motion of the fish that was dropped by the seagul is that of a projectile motion. This motion is made up of two other motions which are, a horizontal uniform motion and a vertical motion, at constant acceleration. From the question, we are asked to find the horizontal motion. And then, the horizontal component of the fish's velocity does not change, therefore its the horizontal component of the fish's velocity is 2.85 m/s
To find the vertical component of the fish's velocity, we use the equation
v(y) = u(y) + gt
Where u(y) is the initial velocity which is zero, and g is the acceleration due to gravity which is -9.8 m/s. We are also told from the question that it took 2.45 s, and that's our time t. Applying this into the equation, we have
v(y) = 0 + -9.8 * 2.45
v(y) = -24.01 m/s
For the 3rd part, the horizontal component of the fish's velocity would decrease
The chemical formula for water, H2o means that each water molecule contains one oxygen atom and two hydrogen atoms. This is the formula for water which has a liquid form, a solid form as ice, and also a gaseous form as water vapor.
Answer:
3ohms
Explanation:
From Ohm's Law
V = IR
V is that voltage = 3volts
I = current = 1amp
R = resistance in ohms
Putting those values into the above formula.
3volts = 1amp×R
Making R the subject
R = 3/1
R = 3ohms
The resistance of the light bulb is 3ohms.
Answer: 495.05 m
Explanation:
Given:
Initial velocity of the bullet, u = 1000 m/s, mass of the bullet, m = 10 g, mass of the wooden block, M = 1000 g,
From the swinging of the wooden block just after the collision with the bullet to its maximum height, using conservation law of mechanical energy we have that,
1/2(m+M) = (m+M)gh
Where h = the vertical height of the block in the direction will the block swing, and g = acceleration due to gravity = 10
=> v=
Using the conservation law of linear momentum,
mu = (m+M)v
mu = (m+M) (where v=)
=>h = *
h=
I don't think so, because in order to produce an image, you need a surface behind the mirror. The light will hit the mirror, then it will bounce it back in your eyes and you see the image.