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AleksAgata [21]
3 years ago
8

What is the special feature of the upper mantle?

Physics
1 answer:
mote1985 [20]3 years ago
3 0
The special feature of the upper mantle is the asthenosphere.It is located just below the lithosphere and is made up of rocks that is fluid and can move.The fluidity of these rocks powered the movement of the tectonic plates on the earths crust.Circular convection cycles in the hot,fluid upper mantle rock move the plates over the surface of the earth.
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How often do we have a solar eclipse or a lunar eclipse?
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In most calendar years there are two lunar eclipses; in some years one or three or none occur. Solar eclipses occur two to five times a year, five being exceptional
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3 years ago
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George Washington Gale Ferris, Jr., a civil engineering graduate from Rensselaer Polytechnic Institute, built the original Ferri
MA_775_DIABLO [31]

Answer:

KE = 4217 J

Explanation:

As we know that the wheel is rotated at constant angular speed

so here we can say that the angular speed is given as

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{2 \times 60}

\omega = 0.052 rad/s

now the moment of inertia of all passengers is given as

I = 36(60)(\frac{76}{2})^2

I = 3119040 kg m^2

now work done by machine must be equal to kinetic energy of the system

so we will have

KE = \frac{1}{2}I\omega^2

KE = \frac{1}{2}(3119040)(0.052)^2

KE = 4217 J

7 0
3 years ago
What is the volume of a cube with length = 3 centimeters, width = 3
suter [353]

Answer:

D. 27 cubic centimeters

Explanation:

l*w*h

3*3*3= 27

4 0
3 years ago
In an experiment, the independent variable is what?
ella [17]
A variable is any factor, trait, or condition that can exist in differing amounts or types. An experiment usually has three kinds of variables: independent, dependent, and controlled. The independent variable is the one that is changed by the scientist.
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3 years ago
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Algebraicallycalculate the rise time and fall timevalues for a sine wave at an arbitrary frequency f0(expressed in Hz). Assume t
Blababa [14]

Answer:

185.95 μsec

Explanation:

Given that:

Sine wave = Amsinw_{o}t

V_{min}=-V_{max}

Sinusodial signal f_{o}  = 50 kHz = 5*10^4Ht

Rise time is said to be defined as the time needed for a pulse to rise from 10% - 90% of maximum rate.

∴

t_1 = 10% = 0.1 Am

t_2 =90% = 0.9 Am

Using sine wave for  t_1; we have:

Amsinw_{o}t_1  = 0.1 Am

sinw_{o}t_1 = 0.1

w_{o}t_1 = sin^{-1}(0.1)

w_{o}t_1 = 5.7392

t_1=\frac{5.7392}{2 \pi f_0}

t_1=\frac{0.9134}{ f_0}

Using sine wave for t_2 ; we have:

Amsinw_{o}t_2  = 0.9 Am

sinw_{o}t_2  = 0.9

w_ot_2 = sin^{-1}(0.9)

w_ot_2 = 64.158

t_2 = \frac{64.1581}{2 \pi f_o}

t_2 = \frac{10.211}{f_o}

Change in rise time t_r = t_2 -  t_1

t_r = \frac{10.211}{f_o}-\frac{0.9134}{ f_0}

t_r = \frac{10.211-0.9134}{f_o}

t_r = \frac{9.2976}{f_o}

since;   f_{o}  = 50 kHz = 5*10^4Ht

t_r = \frac{9.2976}{5*10^4}

t_r = 1.85952 × 10⁻⁴

t_r = 185.952 × 10⁻⁶ sec

t_r =  185.95 μ sec

∴ The rise in time in (μ sec) for the sinosodial signal at 50 kHz = 185.95 μ sec

8 0
3 years ago
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