Answer:
B
Explanation:
Because vector Y is longer than vector X
so when you take a magnitude( without minus ) each other
you see that Y>X
Answer:
424.26 m/s
Explanation:
Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q
The relative speed will be calculated by using pythagorean theorem
Relative speed = sqrt(300^2 + 300^2)
Relative speed = sqrt( 180000 )
Relative speed = 424.26 m/s
Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s
Answer:
Since the hockey puck is moving at constant velocity
So here we will have
where we have
a = acceleration of the object
m = mass of object
so here since we know that acceleration is defined as rate of change in velocity
so here we will say that
so we have
so we will say that hockey puck is in equilibrium as there is no net force of it
