Complete Question
The complete question is shown on the first uploaded image
Answer:
The slit width
Explanation:
Assuming the unit on the graph is cm
Given that the slit to screen distance is D = 200 cm = 20 000 m
The wavelength = 633 nm =
slit width a = ?
The width of the spot that is the width of the peak from the graph is
W = 1.6 × 2 = 3.2 cm
Where the 1.6 is the distance from 0 to the right end point of the peak
The change in y i.e has a formula
= Ltanθ
An the width of the spot is 2 ×
W = 2Ltanθ
Applying this formula qsinθ = m
where m = 1 because we a focused on the first zeros ,using small angle approximation we have y
Substituting this into W = 2ltanθ
Using small angle approximation
W = 2ltanθ = 2Lθ
and this is the slit width
The difference in speed is due to the different densities of the two mediums.
In fact, the higher the density of the medium, the greater the speed of sound. Sound travels faster in liquids (e.g. water) than in gases (e.g. air) because liquids are more dense than gases. This is due to the fact that in liquids, molecules are closer to each other, and since sound is essemptially vibration of molecules, these vibrations are transmitted faster from molecule to molecule in a more dense medium (such as a liquid) rather than in a less dense medium (such as a gas)
Answer: frequency of 3.6 x 10^14 Hz
Explanation:
If someone have two waves, one with a frequency of 4.4 x 1010 Hz and one with a frequency of 3.6 x 1014 Hz, the one with higher frequency ( 3.6 × 10^14) will have the higher energy.
From electromagnetic spectrum,
E = hf
Where
E = energy
F = frequency
h = Planck constant
The one with higher frequency will have the higher energy since energy is directly proportional to the frequency.
Answer:
μs = 0.333 and μk = 0.24
Explanation:
Mass of crates = 22kg
F = 72newton
F =μR
Also given that g = 9.8m/s^2 which is that acceleration due to gravity
Hence R = N = mg
= 9.8 × 22
= 215.6 newton
F is frictional force
μ is coefficient of friction
N or R is normal reaction
Hence, the static friction
F =μsR
72 = μs × 215.6
μs = 72/215.6
μs = 0.333
The kinetic friction coefficient
F =μkR
When F = 52N and R = N = 215.6N
52 = μk × 215.6
μk = 52/215.6
μk = 0.24