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Ad libitum [116K]
2 years ago
8

a rock of mass of 540 g in the air is found to have an apparent mass of 342 g when submerged in water (a) calculate the weight o

f the Rock given that the acceleration of the air g 10 m / s² to ignore the air resistance​
Physics
1 answer:
kupik [55]2 years ago
7 0

Answer: 5.4 N

Explanation:

Given

mass of rock in the air  is 540 g

Apparent mass of 342 gm when submerged in water

Weight of the rock is the product of mass and accleration due to gravity

\Rightarrow W=mg\\\Rightarrow 0.540\times 10=5.4\ N

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3 years ago
1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice
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1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

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3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

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Total amount of heat in the water

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Total amount of heat in the water

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Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

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Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase

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3 years ago
Use the equation for magnetic force on a moving charge to derive the equation for magnetic force on a current carrying wire. Sho
max2010maxim [7]

Answer:

The formula comes from Lorentz force law which includes both the electric and magnetic field. If the electric field is zero, the force law for just the magnetic field is <u>F=q(ν×B</u>) . Here, F  is force and is a vector because the force acts in a direction.  q  is the charge of the particle.  v  is velocity and is a vector because the particle is moving in some direction.  B is the magnetic flux density.

We can derive an expression for the magnetic force on a current by taking a sum of the magnetic forces on individual charges. (The forces add because they are in the same direction.) The force on an individual charge moving at the drift velocity vd.  Since the magnitude of B is constant at every line element of the loop (circle) and it dot product with the line element is B dl everywhere, therefore

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                                                  B ∮dl=μ0 I

                                                  B 2πr=μ0 I

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Since, r can be written as r=(rcosθ,rsinθ,z) and dl as dl=(dl,0,0) And now, if we take the cross product we would get

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and therefore the magnitude of dB is equal to

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Aleks04 [339]

The capacitance of the capacitor is 1.8\cdot 10^{-9}F

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Therefore, the capacitance of the  capacitor is

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