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Ad libitum [116K]
3 years ago
8

a rock of mass of 540 g in the air is found to have an apparent mass of 342 g when submerged in water (a) calculate the weight o

f the Rock given that the acceleration of the air g 10 m / s² to ignore the air resistance​
Physics
1 answer:
kupik [55]3 years ago
7 0

Answer: 5.4 N

Explanation:

Given

mass of rock in the air  is 540 g

Apparent mass of 342 gm when submerged in water

Weight of the rock is the product of mass and accleration due to gravity

\Rightarrow W=mg\\\Rightarrow 0.540\times 10=5.4\ N

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A bar magnet is cut in half, as shown.
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a solenoid that is 98.6 cm long has a cross-sectional area of 24.3 cm2. There are 1310 turns of a wire carrying a current of
Natalija [7]

Complete question:

A solenoid that is 98.6 cm long has a cross-sectional area of 24.3 cm2. There are 1310 turns of a wire carrying a current of 6.75 A. (a) Calculate the energy density of the magnetic field inside the solenoid. (b) Find the total energy stored in the magnetic field there (neglect end effects).

Answer:

(a) the energy density of the magnetic field inside the solenoid is 50.53 J/m³

(b) the total energy stored in the magnetic field is 0.121 J

Explanation:

Given;

length of the solenoid, L = 98.6 cm = 0.986 m

cross-sectional area of the solenoid, A = 24.3 cm² = 24.3 x 10⁻⁴ m²

number of turns of the solenoid, N = 1310 turns

The magnitude of the magnetic field inside the solenoid is given by;

B = μ₀nI

B = μ₀(N/L)I

Where;

μ₀ is permeability of free space, = 4π x 10⁻⁷ m/A

B = \frac{4\pi*10^{-7}*1310*6.75}{0.986} \\\\B = 0.01127 \ T

(a) Calculate the energy density of the magnetic field inside the solenoid

u = \frac{B^2}{2 \mu_o}\\\\u = \frac{(0.01127)^2}{2*4\pi *10^{-7}} \\\\u = 50.53 \ J/m^3

(b) Find the total energy stored in the magnetic field

U = uV

U = u (AL)

U = 50.53 (24.3 x 10⁻⁴  x 0.986)

U = 0.121 J

8 0
3 years ago
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