a car going at 30 m/s undergoes an acceleration of 2 m/(s^2) for 4 seconds. how far did it travel while accelerating?

How dose an atom change if all of its electrons are removed

cluponka [151]

Answer:

The atom becomes a positively charged ion.

Explanation:

The building blocks of an atom are protons, neutrons, and electrons.
The protons and neutrons present in the core of the atom are called nucleus.
The electrons are scattered in an ordered way around the nucleus.
The protons are positively charged and the electrons are negatively charged particles. The neutrons do not possess any charges.
Binding energy is supplied to the atom to remove an electron.
It is possible to remove the electrons of the lighter elements.
When an electron is removed from the hydrogen atom. It becomes positively charged ion or simply proton.
When all of the electrons are removed from the helium atom, it becomes a positively charged α particle.
It is practically very difficult to remove all of the electrons from the heavier elements.
When all of the electrons are removed from an atom it becomes an unstable positively charged ion.

7 0

3 years ago

Compare the catching of two different water balloons.

Stels [109]

Answer:

a. The volume V₁ and V₂

b. The case that involves the greatest momentum change = Case B

c. The case that involves the greatest impulse = Case B

d. b. The case that involves the greatest force = Case B

Explanation:

Here we have

Case A: V₁ = 150-mL, v₁ = 8 m/s

Case B: V₂ = 600-mL, v₁ = 8 m/s

a. The variable that is different for the two cases is the volume V₁ and V₂

b. The momentum change is by the following relation;

ΔM₁ = Mass, m × Δv₁

The mass of the balloon are;

Δv₁ = Change in velocity = Final velocity - Initial velocity

Mass = Density × Volume

Density of water = 0.997 g/mL

Case A, mass = 150 × 0.997 = 149.55 g

Case B, mass = 600 × 0.997 = 598.2 g

The momentum change is;

Case A: Mass, m × Δv₁ = 149.55 g/1000 × 8 m/s = 1.1964 g·m/s

Case B: Mass, m × Δv₁ = 598.2/1000 × 8 = 4.7856 g·m/s

Therefore Case B has the greatest momentum change

The case that has the gretest momentum change = Case B

c. The momentum change = impulse therefore Case B involves the greatest impulse

d. Here we have;

Impulse = Momentum change = $F_{average}$ × Δt = mΔV

∴ $F_{average}$ = m·ΔV/Δt

∴ For Case A $F_{average}$ = 149.55×8/Δt = 1196.4/Δt N

For Case B $F_{average}$ = 598.2×8/Δt = 4785.6/Δt

Where Δt is the same for Case A and Case B, $F_{average}$ for Case B >> $F_{average}$ for Case B

Therefore, Case B involves the greatest force.

4 0

3 years ago

Two +1 C charges are separated by 30000 m, what is the magnitude of the force?

Kipish [7]

Answer:

The magnitude of the force is 10 N

Explanation:

Coulomb's Law

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

$\displaystyle F=k\frac{q_1q_2}{d^2}$