A toy balloon has an internal pressure of 1.05 atm and a volume of 5.0 L. The temperature where the balloon is released is 250 C
1 answer:
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(a) f = 5.00 × 10²⁰ Hz, E = 3.32 × 10⁻¹³ J;
(b) f = 1.20 × 10¹⁰ Hz, E = 7.96 × 10⁻²⁴J.
<h3>Explanation</h3>What's the similarity between a gamma ray and a microwave?
Both gamma rays and microwave rays are electromagnetic radiations. Both travel at the speed of light at in vacuum.
where
- f is the frequency of the electromagnetic radiation,
- c is the speed of light, and
is the wavelength of the radiation.
(a)
Convert all units to standard ones.
.
The unit of shall also be standard.
.
For each particle,
,
where
is the energy of the particle,
is the planck's constant where
, and
is the frequency of the particle.
.
(b)
Try the steps in (a) for this beam of microwave with
.
Expect the following results:
, and
.
Answer:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:
Thus, by combining them, we obtain:
Which is related to the general line equation:
Whereas:
It means that we answer to the blanks as follows:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
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