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4 years ago

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Chemistry

1 answer:

slega [8]4 years ago

7 0

I think the second to last one is hypothesis

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What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid?.

marin [14]

Answer:

What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid? The amount of acid that was added.

Explanation:

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2 years ago

The structure that houses dna

Alecsey [184]

The nucleus (plural, nuclei) houses the cell's genetic material, or DNA, and is also the site of synthesis for ribosomes, the cellular machines that assemble proteins. Inside the nucleus, chromatin (DNA wrapped around proteins, described further below) is stored in a gel-like substance called nucleoplasm.

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3 years ago

"Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrochloric acid

timurjin [86]

Answer:

KOH(aq) + HCl(aq) ——-> KCl(aq) + H2O(l)

Explanation:

A neutralization reaction is the chemical reaction between an acid and an alkali to yield salt and water only.

In this particular question, the acid is hydrochloric acid while the alkali is potassium solution. We now write the equation of reaction as follows:

KOH(aq) + HCl(aq) ——-> KCl(aq) + H2O(l)

The salt formed here is KCl otherwise called potassium chloride

3 0

3 years ago

In which of the ions do all x-o bonds (x indicates the central atom) have the same length?

Radda [10]

<span>Answer: All of the ions do all x-o bonds (x indicates the central atom) have the same length.</span>

7 0

4 years ago

A laser pulse with wavelength 525 nm contains 4.40 mj of energy. How many photons are in the laser pulse

Alexandra [31]

The laser pulse in this question has a wavelength of $\lambda=524 nm=525\times 10^{-9}m$ . To solve this problem, we first have to calculate the energy of a single photon in the laser pulse. The equation for calculating the energy of a single photon of an electromagnetic wave is $E=\frac{hc}{\lambda}$ where $c$ is the speed of light, $h$ is planks constant and $\lambda$ is the wave length of the photons.

For this problem, $c=3.0\times 10^8m/s$ , $h=6.63\times10^{-34}J.s$ and $\lambda=525\times 10^{-9}m$ . We use these values to calculate the energy of the photon as shown below,

$E=\frac{hc}{\lambda} \\E=\frac{(6.63\times 10^{32}Js)\times(3.0\times10^8m/s)}{525\times 10^{-9}m} \\E=3.79\times 10 ^{-19}J.$

Now that we know the energy for a single photon, we will divide the total energy given by the energy of one photon to get the number of photons in the pulse. The number of photons $n$ is calculated as shown below,

$n=\frac{4.4\times 10^{-3}J}{3.79\times10^{-19}J} =1.16\times 10^{16}$ . There are $1.16\times 10^{16}$ photons.

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3 years ago