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2 years ago

How many moles are in 2.5L of 1.75 M Na2CO3

Chemistry

2 answers:

ra1l [238]2 years ago

7 0

Answer:

4.4 mol.

Explanation:

Have a great day

Natasha_Volkova [10]2 years ago

4 0

Answer:

4.4 mol.

Explanation:

Hello!

In this case, since the formula for calculating the molarity is:

$M=n/V$

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

$n=V*M$

Thus, we plug in the given data to obtain:

$n=2.5L*1.75mol/L=4.4mol$

Best regards!

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kakasveta [241]

Answer:

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Explanation:

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2) Ionization equilibrium constant, at 25°C, Kw: given

Kw = 1.0 × 10⁻¹⁴

3) Stoichiometric mole ratio:

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4) A solution has a [OH⁻] = 3.4 × 10⁻⁵ M at 25 °C and you need to calculate what the [H₃O⁺(aq)] is.

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Kw = 1.0 × 10⁻¹⁴ M², and

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Then you can substitute the known values and solve for the unknown:

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⇒ [H₃O⁺] = 1.0 × 10⁻¹⁴ M² / ( 3.4 × 10⁻⁵ M ) = 2.9⁻¹⁰ M

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3 years ago

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