Answer:
R = 0.14 Ω
Explanation:
The resistance of a metal is given by the relation
R =
where ρ the resistivity is 5.6 10-8 Ω m, they also give the length and the cross section (area)
Let's reduce the magnitudes to the SI system
L = 200cm (1m / 100cm) = 2.00m
A = 8.0 10⁻⁷ m²
let's calculate
R = 5.6 10⁻⁸
R = 1.4 10⁻¹ Ω
R = 0.14 Ω
The distance is 97720.5 m
From the question, we have
P = 0.06 W × 2 = 0.12 W
d = ?
Sound intensity, I = P/4πd²
I = 10⁻¹² W/m²
10⁻¹² = 0.12/4πd²
d = 97720.5 m
The distance is 97720.5 m
Sound intensity :
The power carried by sound waves per unit area in the direction perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square meter (W/m2) is the SI unit of intensity, which also covers sound intensity. Sound intensity is a measure of how quickly energy moves across a given space. The unit area in the SI measurement system is 1 m2. So Watts per square meter are used to measure sound intensity. As there will be energy flow in certain directions but not in others, sound intensity also provides a measure of direction.
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Answer:
The velocity of the first block is 1.15m/s while of the second block 2.56m/s.
Explanation:
Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.
Therefore, from conservation of momentum
and from conservation of energy
Thus, we have two equations and two unknowns
which has solutions
and
Since the blocks cannot pass through each other, the 0.5kg block cannot have (moves to the left) while the 0.4 kg block has (moves to the right); therefore, we take the first solution for the velocities:
.
Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.
Devices such as <u>hard drives, CD recorders, and Mini DV camcorders </u>are digital devices, and therefore record data digitally, as ones and zeros.
Explanation:
The smooth analog signal matches the recorded sound wave better than the steps of a digital recording.
However, the analog medium the recording is imprinted on can have tiny imperfections that cause cracking and popping noise.
When used in reference to data storage and transmission, analog format is that in which information is transmitted by modulating a continuous transmission signal, such as amplifying a signal's strength or varying its frequency to add or take away data.
Devices such as hard drives, CD recorders, and Mini DV camcorders are digital devices, and therefore record data digitally, as ones and zeros. VCRs, tape players, and record players, on the other hand, are analog devices. This is because they record data linearly from one point to another.
Analog technologies are stilll used in :
- photocopiers.
- old land-line telephones.
- audio tapes.
- old televisions (intensity and color information per scan line)
- VCRs (same as TV)