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Tatiana [17]
3 years ago
10

Una bombilla de incandescencia tiene un filamento de wolframio cuya resistividad es de 5,6 por 10 a la -8 m , su longitud es de

200 cm y su sección es de 8,0 por 10 a la -7 malcuadrado ¿resistencia?
Physics
1 answer:
Amanda [17]3 years ago
5 0

Answer:

  R = 0.14  Ω

Explanation:

The resistance of a metal is given by the relation

         R = \rho \frac{L}{A}

where ρ the resistivity is 5.6 10-8 Ω m, they also give the length and the cross section (area)

Let's reduce the magnitudes to the SI system

        L = 200cm (1m / 100cm) = 2.00m

        A = 8.0 10⁻⁷ m²

let's calculate

       R = 5.6 10⁻⁸  \frac{2.00}{8.0  \ 10^{-7} }

       R = 1.4 10⁻¹ Ω

       R = 0.14  Ω

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Which of newtons laws is illustrated by a squid moving forward by shooting water out behind it? Why?
Dimas [21]
I believe its newtons 3rd law for every action there is an equal but opposite reaction since the squid is moving foward by shooting the water its pushing the squid back as its reaction. Hope this helped !
5 0
4 years ago
A massless rod of length L has a small mass m fastened at its center and another mass m fastened at one end. On the opposite end
konstantin123 [22]

Answer:

onservation of energy

U top = K bottom

(m + m)*g*L = 1/2*I*?^2 where I = m*(L/2)^2 + m*L^2 = 1.25*m*L^2

So 2m*g*L = 1/2*1.25*m*L^2*?^2

So ? = sqrt(3*g*/(1.25*L) ) = sqrt(12g/5L)

3 0
3 years ago
To practice Problem-Solving Strategy 7.2 Problems Using Mechanical Energy II. The Great Sandini is a 60.0-kg circus performer wh
sp2606 [1]

Answer:

v = 15.45 m/s

Explanation:

As per mechanical energy conservation we can say that here since friction is present in the barrel so we will have

Work done by friction force = Loss in mechanical energy

so we will have

W_f = (U_i + K_i) - (U_f + K_f)

here we know that

W_f = F_f . d

W_f = 40 \times 4

W_f = 160 J

Initial compression in the spring is given as

F = kx

4400 = 1100 x

x = 4 m

now from above equation

W_f = (\frac{1}{2}kx^2 + 0) - (mgh + \frac{1}{2}mv^2)

160 = (\frac{1}{2}1100(4^2) + 0) - (60 \times 9.8\times 2.50 + \frac{1}{2}(60)v^2)

160 = 8800 - 1470 - 30 v^2

v = 15.45 m/s

3 0
3 years ago
LVULAN
3241004551 [841]

For this case we have that by definition, the kinetic energy is given by the following formula:

k= \frac {1} {2} * m * v ^ 2

Where:

m: It is the mass

v: It is the velocity

According to the data we have to:

m = 100 \ kg\\v = 9 \frac {m} {s}

Substituting the values we have:

k = \frac {1} {2} * (100) * (9) ^ 2\\k = \frac {1} {2} * (100) * 81\\k = 50 * 81\\k = 4050

finally, the kinetic energy is 4050 \ J

Answer:

Option A

7 0
4 years ago
a runner covers the last straigjt stretch of a race in 4 s. during that time, he speeds up from 5m/s to 9m/s.
PtichkaEL [24]

During that final period of time,
his acceleration is
                                (9 m/s - 5 m/s) / (4 sec) = 1 m/s² .

Did you have a question to ask ?

8 0
3 years ago
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