<span>Your equation for the height of the stone at any time is h(t) = -16t2<span> + 128t + 32 .
From your equation, we can tell that you're defining the upward direction as
positive. We can also tell that you threw the stone upward, with an initial speed
as it left your hand of 128 feet per second, about 87 miles per hour ... a mighty toss indeed, and I think there's a man from the Chicago Cubs waiting outside
who'd like to talk to you.
Anyway, When the stone splashes into the water, h(t) = 0 .
</span></span>
<span>-16t²<span> + 128t + 32 = 0</span></span>
Divide each side by -16 :
t² - 8t - 2 = 0
I don't see any easy way to factor the expression on the left,
so I have to use the quadratic formula to solve this equation.
t = 4 plus and minus √18 .
t = +8.24 seconds
t = -0.24 second
Mathematically, both numbers are valid solutions.But when you apply
the equation to a real world situation, only the positive 't' makes sense.
So <u> t = 8.24 seconds</u>.
??? What do you need help with/
Answer:
453.25 MJ
Explanation:
The formula to find kinetic energy is :
E.k = ?
m = 0.56kg
v = 25mi./s which needs to be converted into metres per second
1mi./s= 1609.34m/s
25 mi./s = 40233.6 m/s.
E.k. = 0.5 × 0.56 × 40233.6²
e.k = 453247919.3J
E.k.= 453.25 MJ
Answer: 0.313 rad/s
Explanation:
The equation that relates the velocity and the angular velocity in the uniform circular motion is:
(1)
Where is the radius of the space station (with a diaeter of 200m) that describes the uniform circular motion.
Isolating from (1):
(2)
On the other hand, we are told the “artificial gravity” produced by the cetripetal acceleration is , and is given by the following equation:
(3)
Isolating :
(4)
(5)
Substitutinng (5) in (2):
(6)
This is the angular velocity that would produce an “artificial gravity” of 9 .
Answer:
No de español muy bien por favor pregúntalo en inglés
Explanation: