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nika2105 [10]
3 years ago
11

If a triangle has side lengths of 14, 48, and 50 units respectively, what type of triangle is it? An acute, obtuse, or right? Or

does it have no solution?​​
Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

I think it would be a obtuse triangle.

Step-by-step explanation:

Considering the Triangle Inequality theorem, for sides to make a triangle to two smallest sides must have a greater sum then the longest. Now that we know its a triangle we must decided what type of triangle it is. You can rule out acute because of the 14. Now, I used the 3:4:5 right triangle rule, which states that a right triangle must a a ratio of 3:4:5. Again, I think the 14 causes the triangle to be obtuse.

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One morning, John drive 5 hours before stopping to eat. After lunch, he. increased his speed by 10 mph. If he completed a 500-mi
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So  he drove 5hrs, before lunch, now, he was going at speed, say "r", after he ate, he sped up by 10mph, so, his rate is whatever "r" is, plus 10, or " r + 10 ", after lunch

we know the whole trip took 10hrs, so, is 5hrs before lunch and 5hrs after lunch

we also know the whole trip was 500miles, so if he drove, say "d" miles before lunch, after lunch he drove the slack after lunch, or " 200 - d "

recall, your d = rt, distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{before lunch}&d&r&5\\
\textit{after lunch}&500-d&r+10&5
\end{array}
\\\\\\

\begin{cases}
\boxed{d}=5r\\
500-d=(r+10)5\\
----------\\
500-\boxed{5r}=(r+10)5
\end{cases}
\\\\\\
\cfrac{500-5r}{5}=r+10\implies 100-r=r+10

and I'm sure you know what that is
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