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nika2105 [10]
3 years ago
11

If a triangle has side lengths of 14, 48, and 50 units respectively, what type of triangle is it? An acute, obtuse, or right? Or

does it have no solution?​​
Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

I think it would be a obtuse triangle.

Step-by-step explanation:

Considering the Triangle Inequality theorem, for sides to make a triangle to two smallest sides must have a greater sum then the longest. Now that we know its a triangle we must decided what type of triangle it is. You can rule out acute because of the 14. Now, I used the 3:4:5 right triangle rule, which states that a right triangle must a a ratio of 3:4:5. Again, I think the 14 causes the triangle to be obtuse.

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After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only three women among the last
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Answer:

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

Step-by-step explanation:

For each employee hired, the are only two possible outcomes. Either it is a man, or it is a woman. The probability of a person hired being a man or a woman is independent of any other person. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

21 new employees.

This means that n = 21

She also learns that the pool of applicants is very large, with an approximately equal number of qualified men as qualified women.

This means that p = 0.5

Help her address the charge of gender discrimination by finding the probability of getting three or fewer women when 21 people are hired.

This is

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{21,0}.(0.5)^{0}.(0.5)^{21} \approx 0

P(X = 1) = C_{21,1}.(0.5)^{1}.(0.5)^{20} = 0.00001

P(X = 2) = C_{21,2}.(0.5)^{2}.(0.5)^{19} = 0.0001

P(X = 3) = C_{21,3}.(0.5)^{3}.(0.5)^{18} = 0.0006

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.00001 + 0.0001 + 0.0006 = 0.00071

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

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Step-by-step explanation:

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