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nika2105 [10]
3 years ago
11

If a triangle has side lengths of 14, 48, and 50 units respectively, what type of triangle is it? An acute, obtuse, or right? Or

does it have no solution?​​
Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

I think it would be a obtuse triangle.

Step-by-step explanation:

Considering the Triangle Inequality theorem, for sides to make a triangle to two smallest sides must have a greater sum then the longest. Now that we know its a triangle we must decided what type of triangle it is. You can rule out acute because of the 14. Now, I used the 3:4:5 right triangle rule, which states that a right triangle must a a ratio of 3:4:5. Again, I think the 14 causes the triangle to be obtuse.

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Determine whether the sequence below is a geometric sequence and, if so, find a formula that describes the sequence.
Ierofanga [76]
<span>2, 4, 8, 16, –32, 64, …

Common ratio = 4/2 = 2

16/8 = 2

But -32/16 = -2.

The ratio is not constant, hence it is not a geometric.

D. The sequence is not a geometric sequence.</span>
7 0
3 years ago
Calculate the slope of the line that contains the points (3, 4) and (4, -2).
Maurinko [17]

Answer:

-6

Step-by-step explanation:

slope=y2-y1/x2-x1

=-2-4/4-3

=-6/1

=-6

6 0
3 years ago
Odell spends $55 on supplies to make holiday crafts to sell at a local fair. He decides to sell each craft for $2.50 and wants t
lys-0071 [83]

Answer:

Step-by-step explanation:

Let c represent the minimum number of crafts that Odell must sell at the fair.

Odell spends $55 on supplies to make holiday crafts to sell at a local fair. This means that the total cost of supplying c crafts would be $55

If he decides to sell each craft for $2.50, then the total revenue from selling c crafts would be

2.5c

If he wants to earn more than $130 selling the crafts, the inequality that can be used to determine the minimum number of crafts that Odell must sell at the fair is

2.5c - 55 > 130

6 0
3 years ago
. Which expression is equivalent to 4 – (−7)?
sladkih [1.3K]
The answer A. 7 + 4 because it’s equal to 11 and 4-(-7) is 11
8 0
3 years ago
Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug
babymother [125]

Answer:

The total number of ways of assignment is 314,790,828,599,338,321,972,833,000.

Step-by-step explanation:

In mathematics, the procedure to select <em>k</em> items from <em>n</em> distinct items, without replacement, is known as combinations.

The formula to compute the combinations of <em>k</em> items from <em>n</em> is given by the formula:

{n\choose k}=\frac{n!}{k!(n-k)!}

In this case we need to determine the number of ways in which the drugs are assigned to each mouse.

It is provided that new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes.

Drug A is to be given to 22 mice.

Compute the number of ways to assign drug A to 22 mice as follows:

{60\choose 22}=\frac{60!}{22!(60-22)!}\\\\=\frac{60!}{22!\times 38!}\\\\=14154280149473100

Now the remaining number if mice are: 60 - 22 = 38.

Compute the number of ways to assign drug B to 22 mice as follows:

{38\choose 22}=\frac{38!}{38!(38-22)!}\\\\=\frac{38!}{22!\times 16!}\\\\=22239974430

Now the remaining number if mice are: 38 - 22 = 16.

Compute the number of ways to assign no drug to 16 mice as follows:

{16\choose 16}=\frac{16!}{16!(16-16)!}\\\\=1

The total number of ways of assignment is:

N = {60\choose 22}\times {38\choose 22}\times {16\choose 16}\\\\=14154280149473100\times 22239974430\times 1\\\\=314,790,828,599,338,321,972,833,000

Thus, the total number of ways of assignment is 314,790,828,599,338,321,972,833,000.

8 0
3 years ago
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