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Sergeeva-Olga [200]

2 years ago

5

Check out this app! It's millions of students helping each other get through their schoolwork. https://brainly.app.link/qpzV02Ma

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2 answers:

kotykmax [81]2 years ago

6 0

Answer:

guy you should share this your friends who are not on brainly not those that are on brainly don't mean to be rude but thanks

beks73 [17]2 years ago

3 0

Answer:

OK we appreciate your concern.

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A penguin slides at a constant velocity of 3.57 m/s down an icy incline. The incline slopes above the horizontal at an angle of

igomit [66]

Answer:t=0.81 s

Explanation:

Given

Penguin slides down with constant velocity of 3.57 m/s

as the Penguin Slides with constant velocity therefore $F_{net}$ is zero on Penguin

$F_{net}=mg\sin \theta -f_r$

$f_r=$ friction Force

$f_r=\mu mg$

$\mu =$ coefficient of Kinetic friction

$mg\sin \theta =\mu mg$

$\tan \theta =\mu$

$\mu =\tan 9.85=0.45$

after reaching on floor final velocity of penguin will be zero after time t

thus

$v=u+at$

here $a=\mu g$

$a=0.45\times 9.8=4.41$ (deceleration)

$0=3.57-4.41\times t$

$t=\frac{3.57}{4.41}=0.809$

$t=0.81 s$

8 0

3 years ago

What phase difference between two otherwise identical harmonic waves, moving in the same direction along a stretched string, wil

lora16 [44]

Answer:

$\theta=145$

Explanation:

The amplitude of he combined wave is:

$B=2Acos(\theta/2)\\$

A, is the amplitude from the identical harmonic waves

B, is the amplitude of the resultant wave

θ, is the phase, between the waves

The amplitude of the combined wave must be 0.6A:

$0.6A=2Acos(\theta/2)\\ cos(\theta/2)=0.3\\\theta/2=72.5\\\theta=145$

5 0

3 years ago

Phys-1A Horizontal Practice 2

krek1111 [17]

So basically you, then, finally, you

7 0

2 years ago

Why does a partially inflated weather balloon expand as it rises?

marusya05 [52]

Air pressure pushing in on the balloon decreases as the balloon rises.

3 0

3 years ago

Read 2 more answers

1. An asphalt block has a mass of 90 kg and a volume of 0.075 m. Determines the density of the asphalt.

Kisachek [45]

Answer:

1. Density = 1200[kg/m^3]; 2. Volume= 0.005775[m^3], mass= 15.59[kg]

Explanation:

1. We know that the density is defined by the following expression.

$Density = \frac{mass}{volume} \\where:\\mass=90[kg]\\volume=0.075[m^{3} ]\\density=\frac{90}{0.075} \\density=1200[\frac{kg}{m^{3} }]$

2. First we need to convert the units to meters.

wide = 35[cm] = 35/100 = 0.35[m]

long = 11 [dm] = 11 decimeters = 11/10 = 1.1[m]

Thick = 15[mm] = 15/1000 = 0.015[m]

Now we can find the density using the expression for the density.

$density= \frac{mass}{volume} \\where:\\volume = wide*long*thick\\volume=0.35*1.1*0.015 = 0.005775[m^3]\\\\mass= density*volume = 2700*0.005775 = 15.59[kg]$

7 0

3 years ago