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3 years ago

GIVING BRAINLIEST TO BEST EXPLANATION AND CORRECT ANSWER!!!!!!!

Mathematics

2 answers:

Gnom [1K]3 years ago

8 0

Chill dude.

Stop with the all caps.

Musya8 [376]3 years ago

7 0

25 is the answer.

G = green sweets

Ratio of blue to green = 3:5

Ratios are essentially fractions, and can be converted into fraction form

Therefore, number of blue sweets is 3/5 of green sweets, which can also be represented as 3/5g

Number of green sweets to red sweets is 6:1

We can also flip this ratio around and the ratio would still have the same value.

Number of red sweets to green sweets = 1:6

In fraction form, the number of red sweets is 1/6 of green sweets, which is also 1/6g.

Since there are less than 270 sweets in the box, we can use this expression to represent the sweets in the box:

G + 3/5g + 1/6g < 270

Find a common denominator for the fractions.

5 * 6 = 30, thus a common denominator would be 30.

Since G is a variable with no coefficient, 1 would be implied because no coefficient is present.

So when multiplying G to get a common denominator, the numerator would be 30. 30/30 = 1

G * 30 = 1 * 30

G = 30/30g

Multiply the rest of the numerators and you’ll get:

30/30g + 18/30g + 5/30g < 270

Add.

1 + 18/30g + 5/30g = 1 23/30g

Convert this into an improper fraction.

53/30g < 270

Now divide both sides by 53/30.

(53/30g) ÷ (53/30) < 270 ÷ (53/30)

= g < 270 ÷ (53/30)

Dividing fractions is complex, so you can simply switch the numerator and denominator and multiply:

G < 270 x (30/53)

= g < 8,100/53

Since the number of red sweets to green sweets is 1/6g the number of green sweets, the number of red sweets is 1/6 of 8,100/53.

R = red sweets

R < 8,100/53 x 1/6

8,100 x 1 = 8,100

53 x 6 = 318

R < 8,100/318

318 goes into 8,100 25 times, regardless of any remainder.

Therefore, the greatest possible number of red sweets in the box is 25 red sweets.

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Need help with this math please.

Cerrena [4.2K]

Answer:

Do what it says and i'll give you the answer.

Step-by-step explanation:

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4 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

Find an equation of the line satisfying the given conditions Through (6,4); perpendicular to 3X + 5Y =38

Katyanochek1 [597]

To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the

First, we will need to find the slope of this equation. To find this, we must simplify the equation $3x+5y=38$ into $y=mx+b$ form. Lets do it!

$3x+5y=38$
= $5y = -3x+38$ (Subtract 3x from both sides)
= $y= -\frac{3}{5}x+ \frac{38}{5}$ (Divide both sides by 5)

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is $\frac{5}{3}$ .

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

$\frac{y-y _{1} }{x- x_{1} }=m$

Substituting values, we find that:

$\frac{y-4}{x-6}= \frac{5}{3}$

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that:

$y= \frac{5}{3}x-6$ , which is our final answer.

Thank you, and I wish you luck.

8 0

3 years ago

Read 2 more answers

SEAGULLS A biologist studying seagulls estimates that 5% of the seagulls in a flock have been banded. If 22 of the seagulls have

mina [271]

Answer:

440 seagulls

Step-by-step explanation:

Total number of seagulls in flock = Number of seagulls have banded / Percentage of seagulls have banded

Total number of seagulls in flock = 22 / 5%

Total number of seagulls in flock = 22 / 0.05

Total number of seagulls in flock = 440 seagulls