A bullet of mass 10.0 g is fired into an initially sta -tionary block and comes to rest in the block. The block,of mass 1.00 kg,
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Solution :
Given :
Mass of the baseball, m = 200 g
Velocity of the baseball, u = -30 m/s
Mass of the baseball after struck by the bat, M = 900 g
Velocity of the baseball after struck by the bat, v = 47 m/s
According to the conservation of momentum,
(900 x 47) + (200 x -30) = (900 x ) + (200 x
)
36300 = (900 x ) + (200 x
)
..............(i)
The mathematical expression for the conservation of kinetic energy is
................(ii)
Substituting (i) in (ii)
Solving the equation, we get
The negative velocity is neglected.
Therefore, substituting 96 m/s for in (i), we get
= 19
Thus, only impulse of importance is used to find final velocity.