The acceleration due to gravity for any object, including 1 washer on the string, is always assumed to be m/s2
2 answers:
Answer:
The value of acceleration due to gravity on all objects near the surface of earth will be 9.8 m/s/s or 10 m/s/s(approx)
Explanation:
here we know that all objects near the surface of earth will experience the force of gravity towards the center of earth.
this force of gravity is given as
now to find the acceleration due to this force we can say
here we will have
so acceleration due to gravity for all objects near the earth surface is nearly same or constant
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Answer:
the required revolution per hour is 28.6849
Explanation:
Given the data in the question;
we know that the expression for the linear acceleration in terms of angular velocity is;
= rω²
ω² = / r
ω = √( / r )
where r is the radius of the cylinder
ω is the angular velocity
given that; the centripetal acceleration equal to the acceleration of gravity a = g = 9.8 m/s²
so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m
Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m
so we substitute
ω = √( 9.8 m/s² / 3909.87 m )
ω = √0.002506477 s²
ω = 0.0500647 ≈ 0.05 rad/s
we know that; 1 rad/s = 9.5493 revolution per minute
ω = 0.05 × 9.5493 RPM
ω = 0.478082 RPM
1 rpm = 60 rph
so
ω = 0.478082 × 60
ω = 28.6849 revolutions per hour
Therefore, the required revolution per hour is 28.6849