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Mashutka [201]
2 years ago
8

What is the color of the flame when magnesium burns in air ​

Chemistry
1 answer:
vfiekz [6]2 years ago
6 0

Answer:

Will u give me brainliest

white

In its pure form, it is silvery white, and relatively soft. It burns in air with a brilliant white light, and for this reason is often used in flares and fireworks. Magnesium is used in disposable flash bulbs to generate light for photography, but this use has been largely supplanted by other sources of illumination

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Which statement about silver Ag metal is least reliable
Anna007 [38]
<span>The choices for this question can be found elsewhere and as follows:

Silver is a transition metal with electrons in the d shell.
Silver atoms have 47 protons in their nuclei.
Silver atoms commonly form ions with a +1 charge.

I think the correct answer is the last option. The least reliable information would be that s</span>ilver atoms commonly form ions with a +1 charge.
3 0
2 years ago
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A mixture of H2 and water vapor is present in a closed vessel at 20°C. The total pressure of the system is 755.0 mmHg.
Masja [62]

THE ANSWER IS: <u>737.5</u>

I JUST TOOK THE QUIZ!!!!

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Express the number 4.80x10-1 in standard form
rosijanka [135]
The number in standard form is 0.480
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3 years ago
Calculate the mass percent of Cl in Freon -112 (C2 Cl4 F2), a CFC refrigerant
Karolina [17]

Answer:

The answer to your question is:  69.6 %

Explanation:

Freon -112 (C₂Cl₄F₂)

MW = (12 x 2) + (35.5 x 4) + (19 x 2)

      = 24 + 142 + 38

      = 204 g

                       204 g of C₂Cl₄F₂  -----------------  100%

                       142 g                     -----------------   x

                      x = (142 x 100 ) / 204

                      x = 69.6 %

5 0
3 years ago
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What mass of solid sodium formate (of MW 68.01) must be added to 150 mL of 0.42 mol/L formic acid (HCOOH) to make a buffer solu-
Sergio [31]

Answer:

We need 4.28 grams of sodium formate

Explanation:

<u>Step 1:</u> Data given

MW of sodium formate = 68.01 g/mol

Volume of 0.42 mol/L formic acid = 150 mL = 0.150 L

pH = 3.74

Ka = 0.00018

<u>Step 2:</u> Calculate [base)

3.74 = -log(0.00018) + log [base]/[acid]

0 = log [base]/[acid]

0 = log [base] / 0.42

10^0 = 1 = [base]/0.42 M

[base] = 0.42 M

<u>Step 3:</u> Calculate moles of sodium formate:

Moles sodium formate = molarity * volume

Moles of sodium formate = 0.42 M * 0.150 L = 0.063 moles

<u>Step 4:</u> Calculate mass of sodium formate:

Mass sodium formate = moles sodium formate * Molar mass sodium formate

Mass sodium formate = 0.063 mol * 68.01 g/mol

Mass sodium formate = 4.28 grams

We need 4.28 grams of sodium formate

4 0
3 years ago
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