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RUDIKE [14]
3 years ago
12

What is the BEST first step in converting the standard equation below to slope intercept form?

Mathematics
1 answer:
True [87]3 years ago
3 0
Subtract x

Then divide by 2
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PLEASE HELP ILL MARK BRAILIEST! A rectangle has an area of 4 square meters. The width is 1/5 meter. What is the length of the re
Lesechka [4]

20

Step-by-step explanation:

1/5 x 20 = 4

6 0
3 years ago
Matt walker is paid weekly and earns 3.5% straight commission on sales of $6,500 or less and 5% on sales in excess of $6500.last
Nina [5.8K]
His total sales were "x"

now, we know that 3.5% of "x" plus 5% of "x", will add up to his total commission, including sales of 6500 or less or more

so the commission for 6500 or less, is 3.5% of "x" or (3.5/100)*x -> 0.035x
the commission for above 6500 is 5% or (5/100) * x --> 0.05x

we know, that both commissions added together, are $415

thus

0.035x + 0.05x = 415  <-----   solve for "x"
4 0
3 years ago
What are all the fractions are equivalent to 4/12
GarryVolchara [31]
The answers are 1/3, 2/6, 3/9, 4/12
5 0
3 years ago
Someone please help me
andrezito [222]

Answer:

Eat some mc donolds then ur good

Step-by-step explanation:

3 0
3 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
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