Answer:
(orbital speed of the satellite) V₀ = 3.818 km
Time (t) = 4.5 × 10⁴s
Explanation:
Given that:
The radius of the Earth is 6.37 × 10⁶ m; &
the acceleration of gravity at the satellite’s altitude is 0.532655 m/s
We can calculate the orbital speed of the satellite by using the formula:
Orbital Speed (V₀) = √(r × g)
radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m
= (2.1 × 10⁷ + 6.37 × 10⁶) m
= 27370000
= 2.737 × 10⁷m
Orbital Speed (V₀) = √(r × g)
Orbital Speed (V₀) = √(2.737 × 10⁷ × 0.532655 )
= 3818.215
= 3.818 × 10³
= 3.818 Km
To find the time it takes to complete one orbit around the Earth; we use the formula:
Time (t) = 2 π × 
= 2 × 3.14 × 
= 45019.28
= 4.5 × 10 ⁴ s
Answer:
the mean
Explanation:
The mean (informally, the “average“) is found by adding all of the numbers together and dividing by the number of items in the set: 10 + 10 + 20 + 40 + 70 / 5 = 30. The median is found by ordering the set from lowest to highest and finding the exact middle. The median is just the middle number: 20.
A) It is very dry at the equator because it is so hot.
False. It depends on what else is around.
The Sahara Desert is near the Equator.
But so is the Amazon rain forest.
B) Higher places are usually warmer because they are closer to the Sun.
False. Higher places are usually colder, because the air is thinner.
C) Land masses change the direction of currents.
True
D)The sun provides energy needed for the evaporation process. Gravity allows water droplets to fall as precipitation.
True
Answer:
-2.85 * 10^(-17) J
Explanation:
Parameters given:
Final velocity, v = 9 * 10^6 m/s
Initial velocity, u = 4.5 * 10^6 m/s
Using the conservation of energy formula, total energy is conserved:
K.Ein + PEin = KEf + PEf
K.Ef - K.Ein = P.Ein - P.Ef
=> -∆P.E = K.Ef - K.Ein
∆P.E = K.Ein - K.Ef
∆P.E = ½mu² - ½mv²
∆P.E = ½m[(4.5 * 10^6)² - (9 * 10^6)²]
∆P.E = ½ * 9.31 * 10^(-31) * (-61.25 * 10¹²)
∆P.E = -2.85 * 10^(-17) J
