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Mila [183]
2 years ago
6

If the 250 kg bumper car that you are riding in hits another bumper car that is sitting still while driving 3.5 m/s, how much fo

rce did your bumper car have while moving?
Physics
1 answer:
Vilka [71]2 years ago
3 0

Answer:

875 N

Explanation:

From this question, you didn't state the time taken for the bumper car to move or to hit the other bumper car. In calculations of force, time is often needed, because

Force = mass * acceleration, while

Acceleration = velocity / time, basically

Force = mass * velocity / time.

We have our mass, we have our velocity, but we haven't time. So, for this calculation, I'd assume our time to be 1s.

Going by the formula I stated, we can then say that

Force = 250 * 3.5 / 1

Force = 875 N

This means the force my bumper car have while moving at 3.5 m/s for an estimated time of 1s is 875 N

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Tasya [4]

Answer:

C. Fill two identical pots with equal volumes of salt water and tap water and use a stopwatch to determine the time it takes each pot to boil.

Explanation:

<u>A) is incorrect</u> because Peter should have the same testing environment for both of his experiments.

He should choose the same method of boiling the salt water and tap water because the stovetop and the microwave could also affect the results and make them unreliable.

<u>B) is incorrect</u> because Peter should not estimate the time it takes the salt water and tap water to boil.

Peter should measure and record the amount of time that it takes these substances to boil in order to have an accurate, valid experimental thesis.

<u>C) is correct</u> because Peter uses the same volume of salt water and tap water, fills them into two identical pots, and uses a stopwatch to determine the amount of time it takes each pot to boil.

The stopwatch makes the experiment more valid and accurate compared to the previous methods, and the identical pots and amounts of water help this experiment become even more precise.

<u>D) is incorrect</u> because the variables in the experiment are not controlled amounts and will therefore produce an inaccurate and invalid experiment.

6 0
2 years ago
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ΑΣ Sign A. keeping everything grounded on Earth. C. planes not being able to fly into space. B. making tall skyscrapers safe, D.
stepladder [879]

Answer:

i think that it is c because it not only tells us about what the moon does to the earth it also tells us what the earth does to the moon.

Explanation:

3 0
2 years ago
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If you are driving 95 km????h along a straight road and you look to the side for 2.0 s, how far do you travel during this inatte
Gala2k [10]

Answer:

52.7 m

Explanation:

Given that

speed of the vehicle, v = 95 km/h

time of inattentiveness, t = 2 s

distance travelled, s = ?

Since we have the speed in km/h and the time in s, it would be best if we converted one of them to make sure we have all units in the same rank.

95 km/h = 95 * 1000/3600 m/s

95 km/h = 95000/3600 m/s

95 km/h = 26.38 m/s

Now, we use our derived speed in m/s

Speed of a moving vehicle is given by,

v = s/t, where

v = speed in m/s

s = distance travelled, in m

t = time spent, in s

if we make d the subject of formula by rearranging the equation, we have

s = v * t

distance travelled, s = 26.38 * 2

distance travelled, s = 52.7 m

therefore, during this inattentive period, 52.7 m was travelled.

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2 years ago
I will give Brainliest to WHoever answers truthfully!!!!!T/F net force charge and net electric force are the same thing
MakcuM [25]

Answer:

it's true I'm pretty sure

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3 years ago
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What is the number of electrons that move past a point in a wire carrying 500 A of current in 4.0 minutes
mr Goodwill [35]
The current is defined as the amount of charge Q that passes through a given point of a wire in a time \Delta t:
I= \frac{Q}{\Delta t}
Since I=500 A and the time interval is
\Delta t=4.0 min=240 s
the charge is
Q=I \Delta t=(500 A)(240 s)=1.2 \cdot 10^5 C

One electron has a charge of q=1.6 \cdot 10^{-19}C, therefore the number of electrons that pass a point in the wire during 4 minutes is
N= \frac{Q}{q}= \frac{1.2 \cdot 10^5 C}{1.6 \cdot 10^{-19}C}=7.5 \cdot 10^{23} electrons
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3 years ago
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