A 4 kg mass is moving at 8 m/s collides with a 2 kg mass moving at 5 m/s.
1 answer:
Answer:
V = 7 m/s
Explanation:
Given that,
Mass 1, m₁ = 4 kg
Speed of the object 1, v₁ = 8 m/s
Mass 2, m₂ = 2 kg
Speed of object 2, v₂ = 5 m/s
After the collision, both objects stick together. Let V be the common velocity. Using the conservation of linear momentum to find it.
So, the velocity of two cars is 7 m/s.
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Answer:
Question 1)
a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.
This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,
where α is the angular acceleration.
In order to continue this question, the radius of the drums should be given.
Let us denote the radius of the drums as R, the angular acceleration of drum B is
α = 0.5/R.
b) The distance travelled by the drums can be found by the following kinematics formula:
One revolution is equal to the circumference of the drum. So, total number of revolutions is
Question 2)
a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:
b)