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mario62 [17]
3 years ago
15

A 32.78 g sample of a substance is initially at 22.7 °c. after absorbing 2017 j of heat, the temperature of the substance is 173

.2 °c. what is the specific heat (c) of the substance?
Chemistry
1 answer:
larisa86 [58]3 years ago
3 0
Heat= mass * change in temperature* specific heat
specific heat=409 J/kg K
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If 225 grams of propane are burned in the presence of 125 grams of oxygen, how many grams of water should be expected?
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What is the net ionic equation for the precipitation reaction between BaCl2 and Na2So4? I know the answer ( Ba2+(aq) + SO42-(aq)
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Answer:

Net ionic equation:

Ba²⁺(aq) + SO₄²⁻(aq)  →   BaSO₄(s)

Explanation:

Chemical equation:

BaCl₂ +  Na₂SO₄   →   BaSO₄ + NaCl

Balanced Chemical equation:

BaCl₂(aq) +  Na₂SO₄(aq)   →   BaSO₄(s) + 2NaCl(aq)

Ionic equation:

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq)  →  BaSO₄(s)+ 2Na⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

Ba²⁺(aq) + SO₄²⁻(aq)  →   BaSO₄(s)

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The BaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

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A nonpolar molecule has no separation of charge

Explanation:

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Explanation:

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lol I hate chemical but let me give some advice

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Please go on Khan Academy or look at your notes and I promise you can figure out! Seriously, I am trying to be helpful not like the annoying teacher that says "figure it out"

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