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Shtirlitz [24]
3 years ago
12

Eya is 5 years younger than 3 times Bills age. If Eya is 28 how old is Bill?

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0
Bill's age = x

Eya's age = 3x - 5

Eya is 28

28 = 3x - 5

28 (+5) = 3x -5 (+5)

33 = 3x

33/3 = 3x/3

x = 11

Bill = x

x = 11

Bill is 11 years old

hope this helps
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{x}^{2}  + 9x + 20

Step-by-step explanation:

1) Use FOIL method: (a + b) (c + d) = ac + ad + bc + bd.

{x}^{2}  + 5x + 4x + 20

2) Collect like terms.

{x}^{2}  + (5x + 4x) + 20

3) Simplify.

{x}^{2}  + 9x + 20

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5 0
3 years ago
What is the value of X
ExtremeBDS [4]
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8 0
3 years ago
Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it
Zanzabum

Answer:

\beta=45\degree\:\:or\:\:\beta=135\degree

Step-by-step explanation:

We want to solve \tan \beta \sec \beta=\sqrt{2}, where 0\le \beta \le360\degree.

We rewrite in terms of sine and cosine.

\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}

\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}

Use the Pythagorean identity: \cos^2\beta=1-\sin^2\beta.

\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}

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\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0

This is a quadratic equation in \sin \beta.

By the quadratic formula, we have:

\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }

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\sin \beta=\frac{1}{\sqrt{2} } or \sin \beta=-\frac{2}{\sqrt{2} }

\sin \beta=\frac{\sqrt{2}}{2} or \sin \beta=-\sqrt{2}

When \sin \beta=\frac{\sqrt{2}}{2} , \beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )

\implies \beta=45\degree\:\:or\:\:\beta=135\degree on the interval 0\le \beta \le360\degree.

When  \sin \beta=-\sqrt{2}, \beta is not defined because -1\le \sin \beta \le1

4 0
3 years ago
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faltersainse [42]

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Step-by-step explanation:

6 0
3 years ago
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Harman [31]

-8

Step-by-step explanation:

The gradient or slope of a curve y is simply the derivative of the curve at a point x. So we can proceed as follows

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5 0
2 years ago
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