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2 years ago

For the balanced equation shown below, how many moles of CO2 will react with 0.708 moles of H2O.

Chemistry

1 answer:

fgiga [73]2 years ago

7 0

Answer:

0.5 moles of CO2 will react with 0.708 moles of H2O.

Explanation:

$\sf balanced \ equation = 3CO2 + 4H2O \rightarrow C3H8 + 5O2$

0.708 moles of H2O

using molar ratio:

4H2O : 3CO2

4 : 3

so H2O moles:

$\sf\dfrac{0.708}{4} *3$

$\sf 0.531$ moles of CO2

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What element is on period 5 group/family 11

Alexus [3.1K]

Answer:

Silver

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3 years ago

The vitamin A molecule has the formula C20H30O, and a molecule of vitamin A2 has the formula C20H28O. Deter- mine how many moles

natta225 [31]

Answer:

1.04 moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A

Explanation:

Step 1: Data given

Vitamin A = C20H30O

Vitamin A2 = C20H28O

Step 2: Determine the atoms in vitamin A

Vitamin A has 20 C atoms and 30 H atoms and 1 O-atom

In total we have 51 atoms in vitamin A

Step 3: Calculate numbers of atom in 1 mol

1 mol contains 6.022 * 10^23

For 51 atoms = 51 * 6.022*10^23 = 306 *10^23

Step 4: Determine atoms in vitamin A2

Vitamin A2 has 20 C atoms and 28 H atoms and 1 O-atom

In total we have 49 atoms in vitamin A2

Step 5: Calculate molecules A2

Molecules A2 = 306 *10^23 / 49

molecules A2 = 6.24*10^23

Step 6: Calculate how many moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A.

n = 6.24*10^23 / 6.022*10^23 = 1.04 mol

1.04 moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A

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3 years ago

N2(g) + 3H2(g) => 2NH3(g) Write the reaction again as a balanced reaction

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Answer:Consider the reaction N2(g) + 3H2(g) =; 2NH3(g). If hydrogen gas is added to this system at equilibrium, will the reaction shift towards reactants

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3 years ago

Define energy conservation.

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Energy conservation is the effort made to reduce the consumption of energy by using less of an energy service. This can be achieved either by using energy more efficiently or by reducing the amount of service used. Energy conservation is a part of the concept of Eco-sufficiency

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3 years ago

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an ex

Kay [80]

The question is incomplete. The complete question is :

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.

Solution :

Consider the equation of the reaction between NaOH and $HCl$

NaOH (aq) + HCl (aq) → NaCl(aq) + $H_2O (l)$

The above equation tells us that $1 \text{mole}$ of $NaOH$ reacts with $1 \text{mole}$ of $HCl$ .

So at the equivalence point, the moles of NaOH added = moles of $HCl$ present.

If the volume of the $HCl$ taken = $V_1$ mL and the conc. of $HCl$ = $M_1$ mole/L

The volume of NaOH added up to the color change = $V_2 \text{ and conc of NaOH = M}_2$ mole/L

Moles of $HCl$ taken = $V_1 \ mL \times M_1 \ mol/100 \ mL = V_2M_2 \times 10^{-3}$ moles.

The color change will occur when the moles of NaOH added is equal to the moles of $HCl$ taken.

Thus when $V_1 M_1 \times 10^{-3} = V_2M_2 \times 10^{-3}$

or when $V_1M_1 = V_2M_2$

or $V_2=\frac{V_1M_1}{M_2}$ mL of NaOH added, we observe the color change.

Where $V_1, M_1$ are the volume and molarity of the $HCl$ taken.

$M_2$ is the molarity of NaOH added.

When both the NaOH and $HCl$ are of the same concentrations, i.e. if $M_1=M_2$ , then $V_2=V_1$

Or the 40 mL of $HCl$ will need 40 mL of NaOH for a color change and

30 mL of $HCl$ would need 30 mL of NaOH for the color change (provided the concentration $M_1=M_2$ )

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3 years ago