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TiliK225 [7]
3 years ago
9

ASAP ONLY CORRECT ANSWERS PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEE I RLLY NEED HELPPPPPPP

Physics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

attached below

Explanation:

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A is a non-contact breaking of the basketball rules <br>​
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Homeostatasis will be most affected by the romoval of the
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Read 2 more answers
A 55.6 kg ice skater is moving at 1.73 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole.
GarryVolchara [31]

Answer:

The force exerted by the rope on her arms is 273.7 N = 0.274 kN

Explanation:

Step 1: Data given

Mass of the ice skater = 55.6 kg

Velocity = 1.73 m/s

She then moves in a circle of radius 0.608 m around the pole.

Step 2:

Force exterted by the horizontal rope is the centripetal force acting on theice skater:

Fc = M*ac

⇒ with ac = v²/r

Fc = M * v²/r

Fc = 55.6 * 1.73²/0.608

Fc =273.69 N

The force exerted by the rope on her arms is 273.7 N = 0.274 kN

7 0
3 years ago
One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separat
marin [14]

Answer:

B. 2.77 x 10^{-4} N

Explanation:

The required force can be calculated by:

F = \frac{Kq_{1}q_{2}  }{d^{2} }

Where F is the force between the particles, K is the coulomb's constant (9 x 10^{9} Nm^{2}/C^{2}), q_{1} is the charge on the first particle, q_{2} is the charge on the second particle and d^{2} is the distance between the particles.

So that:

F = \frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9}  }{(0.015)^{2} }

  = \frac{6.2307*10^{-8} }{(2.25*10^{-4} }

  = 2.7692 x 10^{-4}

 The force between the particles is 2.77 x 10^{-4} N.

3 0
3 years ago
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