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morpeh [17]
3 years ago
13

Spontaneous reactions occur if energy _____ and disorder _____.

Chemistry
1 answer:
frez [133]3 years ago
6 0
The answer is D. Decreases, Increases 
You might be interested in
If a gas is 0.8L at 900 mm Hg and 400K, what is the new pressure if the volume decreases to 0.5L and 300K?
mezya [45]

Answer:

The new pressure of the gas is 1080 mmHg

Explanation:

The general equation provides a way to calculate the relationship between changesnp in volume, temperature and pressure of a given mass of gas.

The general gas equation is given as P1V1/T1 = P2V2/T2

Where P1 is initial pressure of gas

V1 is initial volume of gas

T1 is initial temperature of gas

P2 is final pressure of gas

V2 is final volume of gas

T2 is final temperature of gas

From the given question, P1 = 900 mmHg, V1 = 0.8 L, T1 = 400 K, P2 = ?, V2 = 0.5 L, T2 = 300 K

Making P2 subject of the general gas equations:

P2 = P1V1T2/V2T1

P2 = (900 × 0.8 × 300) / (0.5 × 400)

P2 = 1080 mmHg

Therefore, the new pressure of the gas is 1080 mmHg.

5 0
2 years ago
According to your results, rank the household products that you have used according to the strength of acidity?
nikklg [1K]
<span>strongest being phenolic acid with the highest acidity for cleaning very set in stains next it is malt vinegar good for toilets, cane vinegar good for floors and skirting board and white wine vinegar good for mixing with citric acid to clean and as already previously stated citric acid</span>
4 0
3 years ago
Salt formed by the partial neutralization of an acid by a base are
Makovka662 [10]

Answer:

D. Acidic salt

Explanation:

Acidic salts:

Salts formed by incomplete neutralisation of poly-basic acids are called acidic salts. Such salts still contain one or more replaceable hydrogen atoms. These salts when neutralised by bases form normal salts.

4 0
3 years ago
What’s the electron configuration of an N-3 ion
Alla [95]

Answer:

1s2 2s2 2p6

Explanation:

The nitride ion(N^3-) is formed when nitrogen gains three electrons. Nitrogen possesses seven electrons in its orbitals and ordinarily has the electronic configuration; 1s2 2s2 2p3. However,being in group 15, nitrogen can accept three electrons to form the nitride ion and complete its octet of electrons. When this happens, three electrons are added to the nitrogen atom and the electronic configuration is now the same as that of Neon, its closest noble gas which is 1s2 2s2 2p6. Hence the answer given above.

Elements can accept or donate electrons in order to complete their octet structure in accordance to the octet rule which states that atoms and ions must possess eight electrons in their outermost shell in order to attain chemical stability. The reason for ion formation and chemical reaction is in order for species to attain the octet structure.

8 0
3 years ago
11. What is the specific heat of a substance with a mass of 25.5 g that requires 412 J
Romashka-Z-Leto [24]

Answer:

297 J

Explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

6 0
3 years ago
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