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Vanyuwa [196]
3 years ago
13

Suppose you are 80 cm from a plane mirror. What area of the mirror is used to reflect the rays entering one eye from a point on

the tip of your nose if your pupil diameter is 6.7 mm ?
Physics
1 answer:
Stells [14]3 years ago
8 0

Answer:

area = 3.5238 ×10^{-5} m²

Explanation:

Given data

distance = 80 cm

diameter = 6.7 mm

to find out

area of the mirror

solution

we know that by similar triangles

diameter of the spot is use by mirror

so

we calculate radius by diameter is 6.7 mm

so radius = 6.7 /2 = 3.35 mm

radius = 0.00335 m

so

area = πr²

area = π(0.00335)²

area = 3.5238 ×10^{-5} m²

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A toy car is placed 29.0cm from a convex mirror. The image of the car is upright and one-sixth as large as the actual car. Calcu
borishaifa [10]

Answer:

The power of the mirror is -17.24 diopter.

Explanation:

Magnification of an image,m = \frac{1}{6}

Distance of the object from the mirror = u = 29.0 cm

Distance of an image from the mirror = v

Magnification = m=\frac{-v}{u}

\frac{1}{6}=\frac{-v}{u}

v=\frac{-u}{6}

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{u}+\frac{-6}{u}

f=\frac{-u}{5}=\frac{-29.0 cm}{5}=-5.8 cm

Focal length of mirror = -5.8 cm =-0.058 m

Power of the lens = P

P =\frac{1}{f}

P=\frac{1}{-0.058 m}=-17.24 D

8 0
3 years ago
A ball is gently dropped from a height of 20 m. If its velocity Increases uniformly at the rate of 10 m s2, with what velocity w
Pie

Answer:

20 m/s

Explanation:

Height (s)= 20m

acceleration (a) = 10 m/s^2

v=?

we know,

V^2= U^2 + 2as. (U is initial velocity)

or,. V^2 = 0 + 2 × 10 × 20

or, V^2 = 400

or,. V = 20 m/s

5 0
2 years ago
Read 2 more answers
A weightlifter curls a 32 kg bar, raising it each time a distance of 0.50 m. How many times must he repeat this exercise to burn
strojnjashka [21]

Answer:

Explanation:

Average energy contained by  a slice of pizza is 860 J  .

energy used in lifting 32 kg bar by .50 m = mgh

= 32 x 9.8 x .5 = 156.8 J

efficiency is 25 % , so energy used up = .75 x 156.8 = 117.6 J

So number of times exercise to be repeated to burn off energy of a slice of pizza

= 860 / 117.6

= 7.3 or 7 times .

4 0
3 years ago
A particle is located on the x axis 4.9 m from the origin. A force of 38 N, directed 30° above the x axis in the x-y plane, acts
Juli2301 [7.4K]

Answer:

Torque is 93 Nm anticlockwise.

Explanation:

We have value of torque is cross product of position vector and force vector.

A force of 38 N, directed 30° above the x axis in the x-y plane.

        Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j

A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.

Position vector, r = 4.9 i

Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm

So Torque is 93 Nm anticlockwise.

7 0
3 years ago
A box with a mass of 0.6-kg falls from a very tall building. While free-falling it is subjected to a frictional drag force given
rjkz [21]

Answer:

1.03m/s

Explanation:

According to the question

Fdrag = bv²

now Fdrag = weight of the box

that is Fdrag = mg

where m = mass of the box, 0.6 Kg

and g = acceleration due to gravity

thus,

Fdrag = bv²   becomes

mg = bv²

making v the subject of formula

v = \sqrt{\frac{mg}{b} }

v = \sqrt{\frac{0.6 * 9.8}{5.5} }

v = 1.03m/s

8 0
3 years ago
Read 2 more answers
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