Suppose you are 80 cm from a plane mirror. What area of the mirror is used to reflect the rays entering one eye from a point on
1 answer:
Answer:
area = 3.5238 × m²
Explanation:
Given data
distance = 80 cm
diameter = 6.7 mm
to find out
area of the mirror
solution
we know that by similar triangles
diameter of the spot is use by mirror
so
we calculate radius by diameter is 6.7 mm
so radius = 6.7 /2 = 3.35 mm
radius = 0.00335 m
so
area = πr²
area = π(0.00335)²
area = 3.5238 × m²
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Answer:
a) V = 0.82m/s
b) Vmax = 0.985 m/s
Explanation:
By conservation of energy we know that:
Eo = Ef
Solving for V we get:
V = 0.82 m/s
To find the maximum speed we will do the same to an intermediate point where the compression is X and the distance for the work donde by frictions is given by (Xmax - X) = (0.28m - X):
Then we have to solve for V, derive and equal zero in order to find position X. After solving the derivative we get:
X = 0.1m Replacing this value into the equation for Vmax:
Vmax = 0.985m/s