Answer:
(p ⋅ 10) − (p ⋅ 2)
Step-by-step explanation:
Try to substitute "p" with any number.
Let's say p = 2
So
p ⋅ (10 − 2)
2 ⋅ (10 − 2)
2 ⋅ (8)
= 16
Now for the other equations
(p ⋅ 10) − (p ⋅ 2)
(2 ⋅ 10) − (2 ⋅ 2)
(20) - (4)
= 16
(10 ⋅ 2) − p
(10 ⋅ 2) − 2
(20 ) − 2
= 18
10 ⋅ 2 − p
10 ⋅ 2 − 2
20 - 2
= 18
(10 ⋅ 2) ⋅ p
(10 ⋅ 2) ⋅ 2
(20) ⋅ 2
= 40
Only (p ⋅ 10) − (p ⋅ 2) has the same result as p ⋅ (10 − 2).
Cheers
Answer:
a - b2
Step-by-step explanation:
STEP 1
:
Trying to factor as a Difference of Squares:
1.1 Factoring: a-b2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : a1 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares
Final result :
a - b2
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Answer is 2nd option
B. WYZ = WZX = ZYX
Answer:
0.42347247428
Step-by-step explanation:
my calcuator
7/16.52
Answer:
N(x) = 40 - 2x
P(x) = -2x² + 52 x - 240
maximum profit = 13
Step-by-step explanation:
given data
feeder cost = $6
average sell = 20 per week
price = $10 each
solution
we consider here price per feeder = x
and profit per feeder id here formula = x - 6
so that here
total profit will be
P (x) = ( x - 6 ) Nx
here N(x) is number of feeders sold at price = x
so formula for N (x) is here
N(x) = 20 - 2 ( x - 10 )
N(x) = 40 - 2x
so that
P(x) = (x-6) ( 40 - 2x)
P(x) = -2x² + 52 x - 240
since here
a = -2
b = 52
c = -240
a < 0
so quadratic function have maximum value of c -
so it will be
maximum value = -240 -
maximum value = 98
so here maximum profit attained at
x = 
x = 
x = 13
maximum profit = 13