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exis [7]
3 years ago
13

Mass of 23.94kg and volume 2.10 cubic centimeters. Calculate the density of the copper wire in si units (ų/mm cubic)

Physics
1 answer:
Kamila [148]3 years ago
7 0

Answer:

Density = 1.14 kg/mm³

Explanation:

Given the following data;

Volume = 2.10 cm³ to mm = 2.10 * 10 = 21 mm³

Mass = 23.94kg

To find the density;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

Density = \frac{mass}{volume}

Substituting into the equation, we have;

Density = \frac{23.94}{21}

Density = 1.14 kg/mm³

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A bag of sugar weighs 3.50 lb on Earth. What would it weigh in newtons on the Moon, where the free-fall acceleration isone-sixth
Alex73 [517]

Answer:

F_{Earth}= 15.57 N

F_{Moon}= 2.60 N

F_{Uranus}= 16.98 N

The mass of the bag is the same on the three planets. m=1.59 kg

Explanation:

The weight of the sugar bag on Earth is:

g=9.81 m/s²

m=3.50 lb=1.59 kg

F_{Earth}=m·g=1.59 kg×9.81 m/s²= 15.57 N

The weight of the sugar bag on the Moon is:

g=9.81 m/s²÷6= 1.635 m/s²

F_{Moon}=m·g=1.59 kg× 1.635 m/s²= 2.60 N

The weight of the sugar bag on the Uranus is:

g=9.81 m/s²×1.09=10.69 m/s²

F_{Uranus}=m·g=1.59 kg×10.69 m/s²= 16.98 N

The mass of the bag is the same on the three planets. m=1.59 kg

5 0
2 years ago
An internal resistance of 5 ohm and a battery of 15 ohm is connected to a resistance of 20 ohm calculate the electric current
Allushta [10]

Answer:

.6 A

Explanation:

Battery 15 VOLTS

V = IR

V / R = I

15 / ( 5+20) = .6 amps

5 0
2 years ago
Which of the following is not a petroleum product
serg [7]
D. wool     
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4 0
3 years ago
Describe what a high and low frequency electromagnetic wave look like:
Ghella [55]
A high electromagnetic wave has short, very fast, frequent waves.

a low electromagnetic wave has long, very slow, infrequent waves.

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4 0
3 years ago
B.A certain piece of copper wire is determined to have a mass of 2.00 g per meter.
masha68 [24]

Answer:

14cm

Explanation:

Mass per gram of the piece of wire;

         2g of the wire is found in 1m

 Since

       100cm  = 1m;

 

So;

       100cm of the wire contains 2g of the wire

To provide 0.28g

 Since;

        2g of wire is made up of 100cm

      0.28g of wire will be contained in \frac{100 x 0.28}{2}   = 14cm

14cm of the wire will contain 0.28g

8 0
3 years ago
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