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IrinaVladis [17]
3 years ago
9

2. Jaimin takes Rs. 10000 at 12% per year as rate of interest, for 2 yean. How much interest he

Chemistry
1 answer:
Annette [7]3 years ago
3 0

Answer:

2400

Explanation:

SI=PRT

p=10000

r=0.12

t=2

si=10000×0.12×2

=2400

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10.6 grams of Na2CO3 is dissolved in water to make 1.25 liters
kipiarov [429]

Answer:

Molarity = 0.08 M

Explanation:

Given data:

Mass of sodium carbonate = 10.6 g

Volume of water = 1.25 L

Molarity of solution = ?

Solution:

First of all we will calculate the moles of solute.

Number of moles = mass/molar mass

Number of moles = 10.6 g/ 106 g/mol

Number of moles = 0.1 mol

Formula:

Molarity = moles of solute / volume of solution in L

Now we will put the values in formula.

Molarity = 0.1 mol / 1.25 L

Molarity = 0.08 M

4 0
2 years ago
Which of these is a chemical property of iron?
denpristay [2]
Iron becomes rusted especially in damp air but never in a dry air,  this is one of the many unique characteristics of iron. Iron is also ductile and malleable. It is found in the seventh group of the periodic table. It has four different and unique crystalline forms and completely dissolves in dilute acids. The two chemical compounds that can be found or made from iron are the bivalent iron also known as ferrous and the trivalent iron or known as ferric compounds.
7 0
3 years ago
Read 2 more answers
Give the correct balanced equation for the single replacement reaction of magnesium with aluminum oxide. A) Mg + AlO → MgO + Al
solniwko [45]
Answer is "C".

<em><u>Explanation
</u></em>

Single replacement reaction is a type of reaction which one reactant reacts with another and makes a product by replacing one element by another. 

Mg (Magnesium) reacts with Al₂O₃ (Aluminium oxide) and produces MgO (Magnesium oxide) and Al (Aluminium) as products. Here Al is replaced by Mg. Reaction is 
             Mg + Al₂O₃ → MgO + Al

To balance the reaction equation, both left and right hand sides should have same number of atoms in each element.
Here, 
 <em>Left Hand Side has </em>                                            <em>Right Hand Side has</em>
   Mg = 1 atom                                                         Mg = 1 atom
   Al = 2 atom                                                           Al = 1 atom
   O = 3 atom                                                           O = 1 atom

First step : balance the O atoms in both sides. To do that "3" should be added before MgO. 

Second step : After balancing O atoms, there will be 3 Mg atoms in right hand side. Hence to balance Mg atoms again "3" should be added before Mg in left hand side

Third step : as the final step balance the Al atoms by adding "2" before Al in the right hand side.

Then final balanced equation should be 
              3Mg + Al₂O₃ → 3MgO + 2Al



 
4 0
3 years ago
Read 2 more answers
These values also increase from the bottom to the top of a group because the size of the atom decreases, resulting in a distance
Allushta [10]

<span>These values also increase from the bottom to the top of a group because the size of the atom decreases, resulting in a smaller distance between the nucleus and the valence electron shell, which increases the attraction between the protons and electrons.</span>

7 0
3 years ago
What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperatu
tatyana61 [14]

Answer:

1) 6.0 atm.

2) 2.066 atm.

Explanation:

  • From the general law of ideal gases:

<em>PV = nRT.</em>

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

<em>1) What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperature is held constant?</em>

  • At constant T and at two different (P, and V):

<em>P₁V₁ = P₂V₂.</em>

P₁ = 2.0 atm, V₁ = 150.0 mL.

P₂ = ??? atm, V₂ = 50.0 mL.

<em>∴ P₂ = P₁V₁/V₂</em> = (2.0 atm)(150.0 mL)/(50.0 mL) = <em>6.0 atm.</em>

<em>2. A sample of a gas in a rigid container at 30.0°C and 2.00 atm has its temperature increased to 40.0°C. What will be the new pressure?</em>

<em></em>

  • Since the container is rigid, so it has constant V.
  • At constant V and at two different (P, and T):

<em>P₁/T₁ = P₂/T₂.</em>

P₁ = 2.0 atm, T₁ = 30.0°C + 273 = 303 K.

P₂ = ??? atm, T₂ = 40.0°C + 273 = 313 K.

<em>∴ P₂ = P₁T₂/T₁ </em>= (2.0 atm)(313.0 K)/(303.0 K) =<em> 2.066 atm.</em>

3 0
3 years ago
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